(Cosx )dY +(sinx)Y=1 anyone who can solve it?

(Cosx )dY +(sinx)Y=1 anyone who can solve it?

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I first divide with cosx. So i get dY+ sinx/cosx Y =cosx..

\[e ^{\int\limits_{}^{}sinx \div cosx} = e ^{-\ln(cosx)} = e^{\ln(cosx)^{-1}} = cosx ^{-1}\]

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