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anonymous
 5 years ago
intergrate cos4x sin7x dx
anonymous
 5 years ago
intergrate cos4x sin7x dx

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it : \[\cos^4xsin^7x?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.01/2 (1/11 cos11x 1/3cos3x_dx is the answer i got

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(1/6) Cos[3 x]  1/22 Cos[11 x]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{}^{}\cos4xsin7x dx =1/2 \int\limits_{}^{}((\sin(3x)+\sin(11x))dx\] (using that sin(7x)cos(4x)=1/2[sin(7x4x)+sin(7x+4x)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[=1/2[{1 \over 3}\cos(3x)+{1 \over 11} \cos(11x)] +c\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{1 \over 6} \cos(3x){1 \over 22} \cos(11x) +c\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if so then:\[\int\limits_{}^{}\cos^4x(1\cos^2x)^4sinx dx\] take : u = cos x du = sinx dx and you'll get : \[=\int\limits_{}^{} u^4(1u^2)^4 dx\] \[= \int\limits_{}^{} u^4(u^8 4u^6 + 2u^4 +1) du\] \[= \int\limits_{}^{}(u^(12) 4u^(10) + 2u^8 +u^4) du\] \[= [u^{13}/13 4u^{11}/11 + 2u^{9}/9 + u^{5}/5] + c\] \[= [\cos^{13}x/13 4\cos^{11}x/11 +2\cos^{9}x/9 +\cos^{5}x/5] + c\] that's the answer if it were cos^4xsin^7x ^_^ correct me if I'm wrong

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or wasn't that the question? ._.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he got two different answers for two different Questions.. lucky him :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0although mine is the answer for his question :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, I'm not sure what was his question and considered it the following ^^"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh then digger, ignore my answer lol, it's for a completely different question ^_^ follow anwar's steps

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no worry's. I'm sure AnwarA is correct as I got the same answer. What are you guys like with 2nd order linear differential equations with constantcoefficents

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Try www.aceyourcollegeclasses.com
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