## anonymous 5 years ago An airplane flies 1200 miles into the wind in 3 hours. The return trip takes 2 hours. Find the speed of the airplane without a wind and the speed of wind.

1. anonymous

from what is given in your question, we have the following two equations: $\nu_{plane}-\nu_{air}={1200 miles \over 3 hours}=400mph \rightarrow(1)$ $v_{plane}+v_{air}={1200 miles \over 2 hours}=600mph$ solve the two equation to find both velocities

2. anonymous

adding equation (1) and (2), we get: $2\nu_{plane}=1000 mph \implies \nu_{plane}=500mph$ substitute in either equation (1) by v_plane=500, you get: $500-\nu_{air}=400mph \implies \nu_{air}=100mph$

3. anonymous

does that make sense to you?

4. anonymous

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5. anonymous

yes it does. thank you very much

6. anonymous

Try www.aceyourcollegeclasses.com

7. anonymous

you're welcome