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anonymous

  • 5 years ago

An airplane flies 1200 miles into the wind in 3 hours. The return trip takes 2 hours. Find the speed of the airplane without a wind and the speed of wind.

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  1. anonymous
    • 5 years ago
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    from what is given in your question, we have the following two equations: \[\nu_{plane}-\nu_{air}={1200 miles \over 3 hours}=400mph \rightarrow(1)\] \[v_{plane}+v_{air}={1200 miles \over 2 hours}=600mph\] solve the two equation to find both velocities

  2. anonymous
    • 5 years ago
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    adding equation (1) and (2), we get: \[2\nu_{plane}=1000 mph \implies \nu_{plane}=500mph\] substitute in either equation (1) by v_plane=500, you get: \[500-\nu_{air}=400mph \implies \nu_{air}=100mph\]

  3. anonymous
    • 5 years ago
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    does that make sense to you?

  4. anonymous
    • 5 years ago
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    Try www.aceyourcollegeclasses.com

  5. anonymous
    • 5 years ago
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    yes it does. thank you very much

  6. anonymous
    • 5 years ago
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    Try www.aceyourcollegeclasses.com

  7. anonymous
    • 5 years ago
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    you're welcome

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