Find the local maximum and minimum values of y= (x)/(xsquared + 4) by using the first and second derivatives.

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Find the local maximum and minimum values of y= (x)/(xsquared + 4) by using the first and second derivatives.

Mathematics
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Take the first derivative of y and set it equal to zero; solve for x and you have your possible minima and maxima. If you take the second derivative, plug in the points you just for, and your value is negative, then you have a maximum at that point. If the second derivative at that point is positive, then you have a minimum.

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