how to find the antiderivative of xroot ofx^2 +1

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how to find the antiderivative of xroot ofx^2 +1

Mathematics
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Wait, is this \[\sqrt[x]{x^2+1}\] or \[x * \sqrt{x^2+1}?\]
x.sqrt(X^2 +1)
If it's the second option (which I think it is), then you have ∫ x √(x^2+1) dx. Let u = x^2+1, and you end up with du = 2x dx. Hence, dx = du/2x, and when you plug it into your integrand, you end up with ∫ 1/2 * √u du. You should be able to solve it after that. :)

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