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## Faith 5 years ago how to find the antiderivative of xroot ofx^2 +1

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1. anonymous

Wait, is this $\sqrt[x]{x^2+1}$ or $x * \sqrt{x^2+1}?$

2. faith

x.sqrt(X^2 +1)

3. anonymous

If it's the second option (which I think it is), then you have ∫ x √(x^2+1) dx. Let u = x^2+1, and you end up with du = 2x dx. Hence, dx = du/2x, and when you plug it into your integrand, you end up with ∫ 1/2 * √u du. You should be able to solve it after that. :)

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