A cyclist bikes at a constant speed for 21 miles . He then returns home at the same speed but takes a different route. His return trip takes one hour longer and is 26 miles. find the speed.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
Solve for X
I don't agree with this... Well, the equation is correct, but when you solve for x you are finding the time not the speed.
speed = distance/time
since the speed is constant, you set the speeds the same
21/x is the speed there and 26/(x+1) is the speed returning
Not the answer you are looking for? Search for more explanations.
When you solve for x you get
21x + 21 = 26x
21 = 5x
x = 4.2 this is time in hours.
Substitute back in r = 21/x and r = 26/(t + 1)
so rate = 21/4.2 = 5 mph and 26/(4.2+1) = 5 mph
I agree you set the speed equal to each other, but the X represents the time in the equation not the rate.
d = rt
21 = rt and 26 = r(t+1) solve for r r = 21/t and r = 26/(t+1)
Set them equal, but you are solving for t which is time.....