## anonymous 5 years ago a water tank is in the form of a right circular cylinder with 20 ft and radius 6 ft. if the tank is half full of water, find the work required to pump all of its water over the rim?

$R=6 ft , H=20 ft$ $A=mg(H-h_{cm})$ m is whole water mass $m=\rho\frac{\pi r^2H}{2}$ $h_{cm}$ is center of mass position $h_{cm}=\frac{H}{4}$ Now you will get $A=\rho\frac{\pi r^2H}{2}g(H-H/4)=\frac{3\pi\rho gr^2H^2}{8}$