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anonymous
 5 years ago
simplify tanx*secx
anonymous
 5 years ago
simplify tanx*secx

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\tan(x) = {\sin(x) \over \cos (x)}\]\[\sec(x) = {1 \over \cos(x)}\]\[\tan(x) \cdot \sec(x) = {\sin(x) \over \cos(x)} \cdot {1 \over \cos(x)} = {\sin(x) \over \cos^2(x)} = \sin(x) \cdot \sec^2(x)\] "simplify" is somewhat ambiguous; in some contexts it means "express in terms of sin and cos", in others "express with no denominators", and so on.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Would\[\sin(x)\over{1\sin(x)^{2}}\] worthy of consideration?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Would\[\sin(x)\over{1\sin(x)^{2}}\] be worthy of consideration?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's usually simpler to have all terms be trig functions, not constants. You could just as easily use \[\sin(x) \cdot \left ( 1 + \tan^2(x) \right )\]
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