anonymous
  • anonymous
what is the exact value of sin15 ? (using the subtraction formula)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
help!
anonymous
  • anonymous
I don't know about the subtraction formula (never heard of it) but the half angle identity should work
nikvist
  • nikvist
\[\sin^215=\frac{1-\cos 30}{2}=\frac{1-\sqrt{3}/2}{2}=\frac{2-\sqrt{3}}{4}\] \[\sin15=\frac{\sqrt{2-\sqrt{3}}}{2}\]

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anonymous
  • anonymous
That's it right there^
anonymous
  • anonymous
I think the subtraction formula would mean that you would take two sin values that you know and use them to get sin 15 Sin 45 - Sin 30 I will get back with the formula
anonymous
  • anonymous
OK here is the formula sin(A−B) = sin A cos B − cos A sin B
anonymous
  • anonymous
im required to use this formula sin(s-t)= sin(s)cos(t) - cos(s)sin(t)
anonymous
  • anonymous
Sin(45-30) = sin45*cos30 - cos45*sin30
anonymous
  • anonymous
Sin 45 = sqrt2/2 cos 45 = sqrt2/2 sin 30 = 1/2 cos 30 = sqrt3/2
anonymous
  • anonymous
The difference identity! Yup that works better!
anonymous
  • anonymous
sqrt2/2*sqrt3/2 - sqrt2/2*1/2 sqrt6/2 - sqrt2/2 (sqrt6 - sqrt2) /2
anonymous
  • anonymous
would it be over 4 after multiplying
anonymous
  • anonymous
OOPS - yes
anonymous
  • anonymous
thanks so much!
anonymous
  • anonymous
U R Welcome

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