anonymous
  • anonymous
what is the exact value of tan15
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
tan(A−B) = (tan A − tan B) / (1 + tan A tan B)
anonymous
  • anonymous
Tan(45 - 15)
anonymous
  • anonymous
OOPS Tan(45 - 30)

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anonymous
  • anonymous
(tan 45 - tan 30)/(1 + tan45*tan30)
anonymous
  • anonymous
Tan 45 = 1 tan 30 = sqrt3/3
anonymous
  • anonymous
(1 - sqrt3/3)(1 + sqrt3/3)
anonymous
  • anonymous
how do you simplify that? the answer is supposed to be 2 - sqrt3
anonymous
  • anonymous
Just a minute... I don't get that answer.. Let me go back thru my math
anonymous
  • anonymous
i got up to where you got before too
anonymous
  • anonymous
OK (1 = sqrt3/3) / (1 + sqrt3/3)
anonymous
  • anonymous
Now you multiply by the conjugate which is (1 - sqrt3/3)/(1-sqrt3/3)
anonymous
  • anonymous
(1 - sqrt3/3)(1 - sqrt3/3) --------------------- (1 + sqrt3/3)(1 - sqrt3/3)
anonymous
  • anonymous
1 - sqrt3/3 - sqrt3/3 + 3/9 ------------------------ 1 - 3/9
anonymous
  • anonymous
1 - 2sqrt3/3 + 1/3 ----------------- 2/3
anonymous
  • anonymous
4/3 - 2sqrt3/3 ------------- 2/3
anonymous
  • anonymous
(4 - 2sqrt3)/3 divided by 2/3 (4 - 2sqrt3)/3 times 3/2
anonymous
  • anonymous
The threes would cancel (4 - 2sqrt3)/2
anonymous
  • anonymous
divide the 2 into each term 2 - sqrt3
anonymous
  • anonymous
how do you find the conjugate again?
anonymous
  • anonymous
The conjugate is basically the denominator but take the opposite sign ex. denominator = 1 - sqrt5 conjugate 1+sqrt5/1+sqrt5
anonymous
  • anonymous
perfect, thanks!
anonymous
  • anonymous
UR welcome
anonymous
  • anonymous
hey, you could use this http://web2.0calc.com/

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