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anonymous

  • 5 years ago

what is the exact value of tan15

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  1. anonymous
    • 5 years ago
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    tan(A−B) = (tan A − tan B) / (1 + tan A tan B)

  2. anonymous
    • 5 years ago
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    Tan(45 - 15)

  3. anonymous
    • 5 years ago
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    OOPS Tan(45 - 30)

  4. anonymous
    • 5 years ago
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    (tan 45 - tan 30)/(1 + tan45*tan30)

  5. anonymous
    • 5 years ago
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    Tan 45 = 1 tan 30 = sqrt3/3

  6. anonymous
    • 5 years ago
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    (1 - sqrt3/3)(1 + sqrt3/3)

  7. anonymous
    • 5 years ago
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    how do you simplify that? the answer is supposed to be 2 - sqrt3

  8. anonymous
    • 5 years ago
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    Just a minute... I don't get that answer.. Let me go back thru my math

  9. anonymous
    • 5 years ago
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    i got up to where you got before too

  10. anonymous
    • 5 years ago
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    OK (1 = sqrt3/3) / (1 + sqrt3/3)

  11. anonymous
    • 5 years ago
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    Now you multiply by the conjugate which is (1 - sqrt3/3)/(1-sqrt3/3)

  12. anonymous
    • 5 years ago
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    (1 - sqrt3/3)(1 - sqrt3/3) --------------------- (1 + sqrt3/3)(1 - sqrt3/3)

  13. anonymous
    • 5 years ago
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    1 - sqrt3/3 - sqrt3/3 + 3/9 ------------------------ 1 - 3/9

  14. anonymous
    • 5 years ago
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    1 - 2sqrt3/3 + 1/3 ----------------- 2/3

  15. anonymous
    • 5 years ago
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    4/3 - 2sqrt3/3 ------------- 2/3

  16. anonymous
    • 5 years ago
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    (4 - 2sqrt3)/3 divided by 2/3 (4 - 2sqrt3)/3 times 3/2

  17. anonymous
    • 5 years ago
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    The threes would cancel (4 - 2sqrt3)/2

  18. anonymous
    • 5 years ago
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    divide the 2 into each term 2 - sqrt3

  19. anonymous
    • 5 years ago
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    how do you find the conjugate again?

  20. anonymous
    • 5 years ago
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    The conjugate is basically the denominator but take the opposite sign ex. denominator = 1 - sqrt5 conjugate 1+sqrt5/1+sqrt5

  21. anonymous
    • 5 years ago
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    perfect, thanks!

  22. anonymous
    • 5 years ago
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    UR welcome

  23. anonymous
    • 5 years ago
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    hey, you could use this http://web2.0calc.com/

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spraguer (Moderator)
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