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anonymous
 5 years ago
Lokisan! Please help me with more differential equations! :)
anonymous
 5 years ago
Lokisan! Please help me with more differential equations! :)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Loki! haha I'm back with more questions. :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you studying exact differential equations?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't think so. I know what the answer is and its not a number. Its the formula of the constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you wait a little bit  I'm just finishing another post.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.022xdy+11ydx+ydy=0 is the actual problem, Sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh, i don't have her question.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Scotty, this looks worse than it is (sorry, I have someone else I'm helping here too).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm hoping so. I think it fits into the trick of d(xy)=dy+ydx am I correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hang on...I misread it...I have to work something out. Sorry, I'll just finish with this other person and I won't be distracted.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so the problem is 22xdy+11ydx+3ydy=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I wish that 22 wasn't there. You sure it's not 11?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know what the answer if, if that helps.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry, I keep being called away.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm thinking a substitution method. Just one sec...again called away...sorry. Won't be forever.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think I may have your method...just let me check properly.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I keep being called away! I'll just let you know what I'm thinking and you can play with it as well. Your equation, when rearranged, looks like this\[y'=\frac{11y}{22x+y}=\frac{11(\frac{y}{x})}{22+(\frac{y}{x})}\]after dividing the numerator and denominator by x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This is in the form for a type of differential equation that can be solved when we know that y' is some function of y/x; that is,\[y'=F(\frac{y}{x})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We make the identification,\[v(x)=\frac{y}{x}\]so that\[y=xv\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and we take it from there. Is this familiar?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok let me try to pmess with it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok instead of that one... can you help me solve y'9y=8e^x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm doing this one for a timed quiz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I figured out your other problem  I made an arithmetic error, but the method is correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah I'll do the second.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok I think I saw where you were going with it and I gutted my way through it. Thanks

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay, integrating factor one  do you know?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not sure what that means..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y'9y=8e^x \rightarrow \frac{d (\mu y)}{dx}=\mu 8e^x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\mu = e^{\int\limits_{}{}9dx}=e^{9x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im sorry that should be y"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[e^{9x}y=e^{9x}.8e^x+c \rightarrow y=ce^{9x}e^x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, sorry for the confusion. I miss typed.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right do you just want the answer for the quiz and then the method

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well. I want to learn but first and foremost I really need to pass this quiz

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I am writing it all down to try to understand though.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=c_1e^{3x}+c_2e^{3x}e^{x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you sure the + isn't a  between the first 2 terms?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have a second order differential equation which is linear, inhomogeneous (because the RHS is a function of x only) with constant coefficients. You need to solve inhom. equations by 1) solving the equivalent homogeneous equation first 2) finding a particular solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In the end, it doesn't matter because it's absorbed into the constant.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The only option I have with a + sign in it is... 2e^3x+e^3xe^x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so e^3x=e^3xe^x is the same thing?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh, do you have initial conditions?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Your equation has it's constants solve for

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh...you need to give me the whole question ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Wait.... y=0 and y'=8 and x=0... I'm sorry I've been up all day doing this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's second order, so there should be 2 conds.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=2e^3xe^{3x}e^x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks so much... I really feel low just asking for answers but I plan on taking the class again. If I fail I have to pay the whole tuition and I've been studying so hard and just not getting it lately :(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's because you're having to do it on your own  you're not being shown the ropes. Don't punish yourself.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0trying not to. Could you help me with 1 or 2 more? Then I'll leave you alone.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How long do you have to do the quiz?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i panic in tests  you shouldn't have told me, lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04xydx=(x^2+4)dy and that is the whole problem and not leaving anything out :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[4xydx=(x^2+4)dy \rightarrow \frac{4xy}{x^2+4}=\frac{dy}{dx} \rightarrow \frac{4x}{x^2+4}dx=\frac{dy}{y}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can integrate from there.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok I think this should be the last one... I think I got the others actually.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's an integrating factor one again.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah those are really difficult for me. Seperatable ones are the ones I'm more comfortable with...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y=\frac{1}{2}e^{4x}+ce^{2x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm just skipping to the solution because of the test...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The closest answer I have that looks like that is e^(4x)+Ce^(2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmmm...that's the solution to the equation you gave me...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let me write it in the formula so it looks better maybe it looks funny on text

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[dy+2ydx=e^{4x}dx \rightarrow y'+2y=e^{4x}\]?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[dy2ydx=6e^(5x) dx\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that dan 5x is super script

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you gave me the wrong question before?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Im a failure sorry I'm rushing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[y(x) = c_1 e^{2 x}+2 e^{5 x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that one available?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes just not written that way but yeah

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I had actually guesed that one after trying to work it myself. Hurray for small miracles.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well... not 100% sure. I think I got the rest of them right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you still want to look at the first one?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For dy+2ydx=e^(4x)dx I got.... y=1/2e^(4x)+ce^(2x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and thats the only other one I kind of guessed on. I do want to look at those though yes.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No I did that one myself

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think its right, not 100% sure though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's the one I did before...and it is...it's right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh ok, sorry I'm scattered. ok I'm submitting it!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What about your first question?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How much time do you have?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the first one was a practice but I do want to know how to do it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How about.... is y'=2y(x3) seperable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok and 2xdx+ysinxdy=sinxdx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's separable too  is that how you solved it?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that one would have taken a bit of effort

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok well it looks all good then :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you so much for that man.....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's okay  i hope you pass

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0have you heard of a site called wolframalpha? www.wolframalpha.com

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok so that original problem..

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can type in things and it will calculate, like your diff. eqs

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but it won't show you what to do, that's the only thing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I have, I don't know how to type these kinds of problems in though.... could you show me how?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm just thinking, if you have more of these tests, you can have a look at that as a resource

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I did use it before, I have 2 more tests actually.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y'2y=e^(4x) is what you can type in for one of your d.e.'s above. It will give you the answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use primes on the y's...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You don't have to tell it to solve for y; it guesses. If it doesn't, then it's a form it doesn't recognize.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hmm.... but even for stuff like... 22xdy+11ydx+3ydy=0?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, divide everything on your paper by dx so you can have (dy/dx) which you can equate as y'

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol... thats a genius way to do it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[22x \frac{dy}{dx}+y+3y \frac{dy}{dx}=0 \rightarrow 22xy'+y+3yy'=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know why they keep giving you the equation in that form...it's weird.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In the form I gave you? Thats the way my teacher gives me them....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, I know...weird.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Almost all my questions are like that is that not how they are normally done?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hmm why would she try to teach like that then?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Maybe she's getting you ready to think in terms of differentials or something. Really, it doesn't matter. Just stick to what she does.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you pass this quiz?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok well I really appreciate it. You might be the only reason I passed that quiz... I'm sure of it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I won't know for a day or two, but I'm sure I did.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Cool, hope so...don't want to be spending more money on tuition...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0god I know. I have...2 more quizes and a final. Then I'll be done with this class.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good luck then. If you need help, look up an old post and send something. I'll get an email about it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok I will man. thanks. Hopefully if you're around I can ask for your help like this again I would star you 1000 times if I could

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No worries. have a go at that first one. The method of substitution v=y/x should work. You end up with a differential equation in v which is separable...and you're comfortable with that ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm going to go offline for a while. I have some stuff to do. Good luck!
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