## anonymous 5 years ago Integrate:

1. anonymous

$\int\limits{\sqrt{4x+1}} dx$

2. anonymous

the answer is $(1/6)[(4x+1)^{3/2}]$ set u = 4x + 1 and du = 4dx \$1/4\int\limits\limits\limits_{}^{}(u ^{1/2)^{}}du$

3. anonymous

cheers