off subject..but can yall help me figure this problem out PLEASE?!
24v^2 + 5v - 36 i have to do the reverse FOIL method

- anonymous

- katieb

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- anonymous

(8x - 9)(3x + 4)

- anonymous

Recognize that\[24v^2+5v-36=8v \times3v+8v \times4-9\times3v-9\times4\]

- anonymous

Take out the common factors,\[8v(3v+4)-9(3v+4)\]

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## More answers

- anonymous

i.e.\[(3v+4)(8v-9)\]

- anonymous

It's the reverse way of going about FOIL.

- anonymous

thank you i find these hard to figure out

- anonymous

Have you been taught the quadratic formula yet?

- anonymous

If not, don't worry, but I was just asking because you can use it to give you a clue as to what factors to use...

- anonymous

umm i dont know...

- anonymous

It's okay. For now, you just have to find the right combination of factors by trial and error.

- anonymous

okay....math is very hard

- anonymous

Yeah, you just have to practice.

- anonymous

what about this one 16x^2 +32xy +15y^2

- anonymous

\[16x^2+32xy+15y^2=4x \times 4x -4x \times 5y-3y \times 4x +2y \times 5y\]

- anonymous

\[=4x(4x-5y)-3y(4x-5y)\]\[=(4x-3y)(4x-5y)\]

- anonymous

Wait up, I stuffed one of the signs...long day

- anonymous

ok

- anonymous

should be

- anonymous

thank you

- anonymous

\[16x^2+32xy+15y^2=4x \times 4x +4x \times 5y+3y \times 4x + 3y \times 5y\]

- anonymous

\[=4x(4x+5y)+3y(4x+5y)\]\[=(4x+3y)(4x+5y)\]

- anonymous

Does your teacher expect you to eyeball solutions to these?

- anonymous

no we have to show work,

- anonymous

that was the last one on that lesson. Now its - Diffrence of Squares and Perfect Square trinomials

- anonymous

How many questions are there?

- anonymous

30

- anonymous

I mightn't be around for much longer. Do you want me to see if there's someone else that can help?

- anonymous

yes please

- anonymous

I'll try to help out, yet I won't be here for long though

- anonymous

oh ok thank you

- anonymous

16a^2- 25b^2

- anonymous

the book says the answer is " no" how is that

- anonymous

you can write it like this too :\[4^2a^2 -5^2b^2\]
all you have to do is simplify it into 2 brackets, give it a try :)

- anonymous

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- anonymous

so you find the square of the 16 and 25

- anonymous

No...

- anonymous

why not?

- anonymous

wait, isn't the question = factor?

- anonymous

You have something in the form,\[a^2-b^2\]These things are called 'difference of two squares' and it factors as\[a^2-b^2=(a+b)(a-b)\]

- anonymous

factor right?

- anonymous

it says for each binomial is the binomial a diffrence of squares

- anonymous

\[16a^2-25b^2=(4a)^2-(5b)^2=(4a-5b)(4a+5b)\]

- anonymous

lol, that's what I've meant loki!

- anonymous

I wanted him to give it a try :)

- anonymous

oops..sorry :(

- anonymous

it's alright :)

- anonymous

dina did you understand the general concept of how to solve the problem?

- anonymous

so its a NO because one is plus and one is minus?!

- anonymous

Your answer is YES

- anonymous

If it factors like it factored above, it is a difference of two squares, so your answer would be YES.

- anonymous

uhhh ok im getting confused lol

- anonymous

try the general formula loki showed you which is :
(a-b)(a+b) use the FOIL method to check whether it's equal to :
\[a^2-b^2\]
as long as you understand the general concept of this question, you'll be able to proceed on your own , okay? :)

- anonymous

Exactly

- anonymous

clear dina? ^_^

- anonymous

i think so

- anonymous

all of the questions are the same, all you have to do is write them in the form of \[a^2-b^2\]
and you\'ll be fine ^_^

- anonymous

then apply the rule which is (a-b)(a+b) and use the FOIL to check your answer, and you'll ace it ! :)

- anonymous

thanks guys!

- anonymous

np ^_^, did you undestand?

- anonymous

So you get it then?

- anonymous

i think for now at least

- anonymous

good!

- anonymous

awesome :) , just practice one to check your understanding

- anonymous

and you'll get it

- anonymous

loki, lemmy get you up top real quick pleasee

- anonymous

ok...16a^2 - 12b^3

- anonymous

(4 + a)

- anonymous

for the first part?

- anonymous

you can take 4 as a common factor , so you'll have:\[4(4a^2-3b^2) = 4(2a -b)(2a+3b)\]
correct me if I'm wrong

- anonymous

That is not correct

- anonymous

First of all he has b^3 and second of all you can't write 3 as a perfect square.
All you can do is take out the 4

- anonymous

lol, I'm rushing can you take the lead blexting>?

- anonymous

Sure...

- anonymous

oh right! i forgot abt b^3

- anonymous

sorry

- anonymous

dina are just trying to factor?

- anonymous

the answers either yes or no

- anonymous

the answers either yes or no

- anonymous

to "is it a perfect square" is that the question?

- anonymous

This last one was NOT a perfect square.

- anonymous

yes

- anonymous

yes

- anonymous

OK.. what is the next one

- anonymous

thats it for now my daughter just wooke up thanks for all the help! i appreciate it

- anonymous

OK

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