## anonymous 5 years ago off subject..but can yall help me figure this problem out PLEASE?! 24v^2 + 5v - 36 i have to do the reverse FOIL method

1. anonymous

(8x - 9)(3x + 4)

2. anonymous

Recognize that$24v^2+5v-36=8v \times3v+8v \times4-9\times3v-9\times4$

3. anonymous

Take out the common factors,$8v(3v+4)-9(3v+4)$

4. anonymous

i.e.$(3v+4)(8v-9)$

5. anonymous

It's the reverse way of going about FOIL.

6. anonymous

thank you i find these hard to figure out

7. anonymous

Have you been taught the quadratic formula yet?

8. anonymous

If not, don't worry, but I was just asking because you can use it to give you a clue as to what factors to use...

9. anonymous

umm i dont know...

10. anonymous

It's okay. For now, you just have to find the right combination of factors by trial and error.

11. anonymous

okay....math is very hard

12. anonymous

Yeah, you just have to practice.

13. anonymous

14. anonymous

$16x^2+32xy+15y^2=4x \times 4x -4x \times 5y-3y \times 4x +2y \times 5y$

15. anonymous

$=4x(4x-5y)-3y(4x-5y)$$=(4x-3y)(4x-5y)$

16. anonymous

Wait up, I stuffed one of the signs...long day

17. anonymous

ok

18. anonymous

should be

19. anonymous

thank you

20. anonymous

$16x^2+32xy+15y^2=4x \times 4x +4x \times 5y+3y \times 4x + 3y \times 5y$

21. anonymous

$=4x(4x+5y)+3y(4x+5y)$$=(4x+3y)(4x+5y)$

22. anonymous

Does your teacher expect you to eyeball solutions to these?

23. anonymous

no we have to show work,

24. anonymous

that was the last one on that lesson. Now its - Diffrence of Squares and Perfect Square trinomials

25. anonymous

How many questions are there?

26. anonymous

30

27. anonymous

I mightn't be around for much longer. Do you want me to see if there's someone else that can help?

28. anonymous

29. anonymous

I'll try to help out, yet I won't be here for long though

30. anonymous

oh ok thank you

31. anonymous

16a^2- 25b^2

32. anonymous

the book says the answer is " no" how is that

33. anonymous

you can write it like this too :$4^2a^2 -5^2b^2$ all you have to do is simplify it into 2 brackets, give it a try :)

34. anonymous

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35. anonymous

so you find the square of the 16 and 25

36. anonymous

No...

37. anonymous

why not?

38. anonymous

wait, isn't the question = factor?

39. anonymous

You have something in the form,$a^2-b^2$These things are called 'difference of two squares' and it factors as$a^2-b^2=(a+b)(a-b)$

40. anonymous

factor right?

41. anonymous

it says for each binomial is the binomial a diffrence of squares

42. anonymous

$16a^2-25b^2=(4a)^2-(5b)^2=(4a-5b)(4a+5b)$

43. anonymous

lol, that's what I've meant loki!

44. anonymous

I wanted him to give it a try :)

45. anonymous

oops..sorry :(

46. anonymous

it's alright :)

47. anonymous

dina did you understand the general concept of how to solve the problem?

48. anonymous

so its a NO because one is plus and one is minus?!

49. anonymous

50. anonymous

If it factors like it factored above, it is a difference of two squares, so your answer would be YES.

51. anonymous

uhhh ok im getting confused lol

52. anonymous

try the general formula loki showed you which is : (a-b)(a+b) use the FOIL method to check whether it's equal to : $a^2-b^2$ as long as you understand the general concept of this question, you'll be able to proceed on your own , okay? :)

53. anonymous

Exactly

54. anonymous

clear dina? ^_^

55. anonymous

i think so

56. anonymous

all of the questions are the same, all you have to do is write them in the form of $a^2-b^2$ and you\'ll be fine ^_^

57. anonymous

then apply the rule which is (a-b)(a+b) and use the FOIL to check your answer, and you'll ace it ! :)

58. anonymous

thanks guys!

59. anonymous

np ^_^, did you undestand?

60. anonymous

So you get it then?

61. anonymous

i think for now at least

62. anonymous

good!

63. anonymous

awesome :) , just practice one to check your understanding

64. anonymous

and you'll get it

65. anonymous

loki, lemmy get you up top real quick pleasee

66. anonymous

ok...16a^2 - 12b^3

67. anonymous

(4 + a)

68. anonymous

for the first part?

69. anonymous

you can take 4 as a common factor , so you'll have:$4(4a^2-3b^2) = 4(2a -b)(2a+3b)$ correct me if I'm wrong

70. anonymous

That is not correct

71. anonymous

First of all he has b^3 and second of all you can't write 3 as a perfect square. All you can do is take out the 4

72. anonymous

lol, I'm rushing can you take the lead blexting>?

73. anonymous

Sure...

74. anonymous

oh right! i forgot abt b^3

75. anonymous

sorry

76. anonymous

dina are just trying to factor?

77. anonymous

the answers either yes or no

78. anonymous

the answers either yes or no

79. anonymous

to "is it a perfect square" is that the question?

80. anonymous

This last one was NOT a perfect square.

81. anonymous

yes

82. anonymous

yes

83. anonymous

OK.. what is the next one

84. anonymous

thats it for now my daughter just wooke up thanks for all the help! i appreciate it

85. anonymous

OK