anonymous
  • anonymous
off subject..but can yall help me figure this problem out PLEASE?! 24v^2 + 5v - 36 i have to do the reverse FOIL method
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
(8x - 9)(3x + 4)
anonymous
  • anonymous
Recognize that\[24v^2+5v-36=8v \times3v+8v \times4-9\times3v-9\times4\]
anonymous
  • anonymous
Take out the common factors,\[8v(3v+4)-9(3v+4)\]

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anonymous
  • anonymous
i.e.\[(3v+4)(8v-9)\]
anonymous
  • anonymous
It's the reverse way of going about FOIL.
anonymous
  • anonymous
thank you i find these hard to figure out
anonymous
  • anonymous
Have you been taught the quadratic formula yet?
anonymous
  • anonymous
If not, don't worry, but I was just asking because you can use it to give you a clue as to what factors to use...
anonymous
  • anonymous
umm i dont know...
anonymous
  • anonymous
It's okay. For now, you just have to find the right combination of factors by trial and error.
anonymous
  • anonymous
okay....math is very hard
anonymous
  • anonymous
Yeah, you just have to practice.
anonymous
  • anonymous
what about this one 16x^2 +32xy +15y^2
anonymous
  • anonymous
\[16x^2+32xy+15y^2=4x \times 4x -4x \times 5y-3y \times 4x +2y \times 5y\]
anonymous
  • anonymous
\[=4x(4x-5y)-3y(4x-5y)\]\[=(4x-3y)(4x-5y)\]
anonymous
  • anonymous
Wait up, I stuffed one of the signs...long day
anonymous
  • anonymous
ok
anonymous
  • anonymous
should be
anonymous
  • anonymous
thank you
anonymous
  • anonymous
\[16x^2+32xy+15y^2=4x \times 4x +4x \times 5y+3y \times 4x + 3y \times 5y\]
anonymous
  • anonymous
\[=4x(4x+5y)+3y(4x+5y)\]\[=(4x+3y)(4x+5y)\]
anonymous
  • anonymous
Does your teacher expect you to eyeball solutions to these?
anonymous
  • anonymous
no we have to show work,
anonymous
  • anonymous
that was the last one on that lesson. Now its - Diffrence of Squares and Perfect Square trinomials
anonymous
  • anonymous
How many questions are there?
anonymous
  • anonymous
30
anonymous
  • anonymous
I mightn't be around for much longer. Do you want me to see if there's someone else that can help?
anonymous
  • anonymous
yes please
anonymous
  • anonymous
I'll try to help out, yet I won't be here for long though
anonymous
  • anonymous
oh ok thank you
anonymous
  • anonymous
16a^2- 25b^2
anonymous
  • anonymous
the book says the answer is " no" how is that
anonymous
  • anonymous
you can write it like this too :\[4^2a^2 -5^2b^2\] all you have to do is simplify it into 2 brackets, give it a try :)
anonymous
  • anonymous
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anonymous
  • anonymous
so you find the square of the 16 and 25
anonymous
  • anonymous
No...
anonymous
  • anonymous
why not?
anonymous
  • anonymous
wait, isn't the question = factor?
anonymous
  • anonymous
You have something in the form,\[a^2-b^2\]These things are called 'difference of two squares' and it factors as\[a^2-b^2=(a+b)(a-b)\]
anonymous
  • anonymous
factor right?
anonymous
  • anonymous
it says for each binomial is the binomial a diffrence of squares
anonymous
  • anonymous
\[16a^2-25b^2=(4a)^2-(5b)^2=(4a-5b)(4a+5b)\]
anonymous
  • anonymous
lol, that's what I've meant loki!
anonymous
  • anonymous
I wanted him to give it a try :)
anonymous
  • anonymous
oops..sorry :(
anonymous
  • anonymous
it's alright :)
anonymous
  • anonymous
dina did you understand the general concept of how to solve the problem?
anonymous
  • anonymous
so its a NO because one is plus and one is minus?!
anonymous
  • anonymous
Your answer is YES
anonymous
  • anonymous
If it factors like it factored above, it is a difference of two squares, so your answer would be YES.
anonymous
  • anonymous
uhhh ok im getting confused lol
anonymous
  • anonymous
try the general formula loki showed you which is : (a-b)(a+b) use the FOIL method to check whether it's equal to : \[a^2-b^2\] as long as you understand the general concept of this question, you'll be able to proceed on your own , okay? :)
anonymous
  • anonymous
Exactly
anonymous
  • anonymous
clear dina? ^_^
anonymous
  • anonymous
i think so
anonymous
  • anonymous
all of the questions are the same, all you have to do is write them in the form of \[a^2-b^2\] and you\'ll be fine ^_^
anonymous
  • anonymous
then apply the rule which is (a-b)(a+b) and use the FOIL to check your answer, and you'll ace it ! :)
anonymous
  • anonymous
thanks guys!
anonymous
  • anonymous
np ^_^, did you undestand?
anonymous
  • anonymous
So you get it then?
anonymous
  • anonymous
i think for now at least
anonymous
  • anonymous
good!
anonymous
  • anonymous
awesome :) , just practice one to check your understanding
anonymous
  • anonymous
and you'll get it
anonymous
  • anonymous
loki, lemmy get you up top real quick pleasee
anonymous
  • anonymous
ok...16a^2 - 12b^3
anonymous
  • anonymous
(4 + a)
anonymous
  • anonymous
for the first part?
anonymous
  • anonymous
you can take 4 as a common factor , so you'll have:\[4(4a^2-3b^2) = 4(2a -b)(2a+3b)\] correct me if I'm wrong
anonymous
  • anonymous
That is not correct
anonymous
  • anonymous
First of all he has b^3 and second of all you can't write 3 as a perfect square. All you can do is take out the 4
anonymous
  • anonymous
lol, I'm rushing can you take the lead blexting>?
anonymous
  • anonymous
Sure...
anonymous
  • anonymous
oh right! i forgot abt b^3
anonymous
  • anonymous
sorry
anonymous
  • anonymous
dina are just trying to factor?
anonymous
  • anonymous
the answers either yes or no
anonymous
  • anonymous
the answers either yes or no
anonymous
  • anonymous
to "is it a perfect square" is that the question?
anonymous
  • anonymous
This last one was NOT a perfect square.
anonymous
  • anonymous
yes
anonymous
  • anonymous
yes
anonymous
  • anonymous
OK.. what is the next one
anonymous
  • anonymous
thats it for now my daughter just wooke up thanks for all the help! i appreciate it
anonymous
  • anonymous
OK

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