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(8x - 9)(3x + 4)
Recognize that\[24v^2+5v-36=8v \times3v+8v \times4-9\times3v-9\times4\]
Take out the common factors,\[8v(3v+4)-9(3v+4)\]
It's the reverse way of going about FOIL.
thank you i find these hard to figure out
Have you been taught the quadratic formula yet?
If not, don't worry, but I was just asking because you can use it to give you a clue as to what factors to use...
umm i dont know...
It's okay. For now, you just have to find the right combination of factors by trial and error.
okay....math is very hard
Yeah, you just have to practice.
what about this one 16x^2 +32xy +15y^2
\[16x^2+32xy+15y^2=4x \times 4x -4x \times 5y-3y \times 4x +2y \times 5y\]
Wait up, I stuffed one of the signs...long day
\[16x^2+32xy+15y^2=4x \times 4x +4x \times 5y+3y \times 4x + 3y \times 5y\]
Does your teacher expect you to eyeball solutions to these?
no we have to show work,
that was the last one on that lesson. Now its - Diffrence of Squares and Perfect Square trinomials
How many questions are there?
I mightn't be around for much longer. Do you want me to see if there's someone else that can help?
I'll try to help out, yet I won't be here for long though
oh ok thank you
the book says the answer is " no" how is that
you can write it like this too :\[4^2a^2 -5^2b^2\] all you have to do is simplify it into 2 brackets, give it a try :)
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so you find the square of the 16 and 25
wait, isn't the question = factor?
You have something in the form,\[a^2-b^2\]These things are called 'difference of two squares' and it factors as\[a^2-b^2=(a+b)(a-b)\]
it says for each binomial is the binomial a diffrence of squares
lol, that's what I've meant loki!
I wanted him to give it a try :)
it's alright :)
dina did you understand the general concept of how to solve the problem?
so its a NO because one is plus and one is minus?!
Your answer is YES
If it factors like it factored above, it is a difference of two squares, so your answer would be YES.
uhhh ok im getting confused lol
try the general formula loki showed you which is : (a-b)(a+b) use the FOIL method to check whether it's equal to : \[a^2-b^2\] as long as you understand the general concept of this question, you'll be able to proceed on your own , okay? :)
clear dina? ^_^
i think so
all of the questions are the same, all you have to do is write them in the form of \[a^2-b^2\] and you\'ll be fine ^_^
then apply the rule which is (a-b)(a+b) and use the FOIL to check your answer, and you'll ace it ! :)
np ^_^, did you undestand?
So you get it then?
i think for now at least
awesome :) , just practice one to check your understanding
and you'll get it
loki, lemmy get you up top real quick pleasee
ok...16a^2 - 12b^3
(4 + a)
for the first part?
you can take 4 as a common factor , so you'll have:\[4(4a^2-3b^2) = 4(2a -b)(2a+3b)\] correct me if I'm wrong
That is not correct
First of all he has b^3 and second of all you can't write 3 as a perfect square. All you can do is take out the 4
lol, I'm rushing can you take the lead blexting>?
oh right! i forgot abt b^3
dina are just trying to factor?
the answers either yes or no
the answers either yes or no
to "is it a perfect square" is that the question?
This last one was NOT a perfect square.
OK.. what is the next one
thats it for now my daughter just wooke up thanks for all the help! i appreciate it