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anonymous
 5 years ago
Find the relative rate of change fro each of the following functions.
f(x)=x^3 3x^2
anonymous
 5 years ago
Find the relative rate of change fro each of the following functions. f(x)=x^3 3x^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you have to derive here, or am I wrong? Since it's about rate of change, right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no this is the problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the derivative would be 3x^2 6x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's how you compute the relative rate of change, by deriving ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im not understanding?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so do i take f'(x) and divide it by f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, to find the relative rate of change, you have to find the derivative of the following function which is in this case :\[f(x) = x^3  3x^2\] so when you derive the function you'll get like what you've said : \[f'(x) = 3x^2  6x\] since there is no given for x, then that's the final equation I guess :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if they told you, for example, that x = 2 then substitute it in the derived function and you'll find the relative rate of change

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0or am I mixing it up with something?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got all that, but my teacher still counted 2 points off?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm, I'm missing a point aren't I?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sstarica, when you're done here, can you help dinaortega? I'm leaving soon.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'll try my best loki :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0could you help me lokisan?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0relative rate of change is f'(x)/f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0>_< thank you blexting

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0blexting so how do i get that from f(x)= x^3 3x^2 being the original problem and f'(x)=3x^2 6x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry.. I don't know, but I knew the formula.. sstarica can you help?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Post your assignment questions at www.aceyourcollegeclasses.com you can earn money answering questions there too!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0divide f'(x) with f(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{f'(x)}{f(x)}=\frac{3x^26x}{x^33x^2}=\frac{3x6}{x^23x}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so you'll get :\[f'(x)/f(x) = (3x^26x)/(x^32x^2)\]\[= 3x(x2)/x^2(x2)\] \[= 3/x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sstarica.. the original was 3x^2. I agree with lokisan

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh , sorry my bad ^^"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is it clearer now ballards?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you guys that makes since, but what if you have a log problem like this... f(x)=5xxlnx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is clear how to figure out the relative rate of change. Could someone help me figure out the f'(x) of that log then i maybe could get it from there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if f(x)=ln(x) f'(x)=1/x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0same story, find the derivative then divide it by the original function ^_^ and you'll get : f'(x) = 5  [lnx + 1] ( use u'v + uv' to find the derivatice of xlnx) then divide it by the original : \[f'(x)/f(x) = (5\lnx1)/ 5x  xlnx\] and try to simplify :) give it a try now.
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