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lokisanBest ResponseYou've already chosen the best response.0
Radicals are just expressions for powers, so you can use power laws to turn your orginal expression into:\[\left( \frac{a^3+b^3}{a+b} \right)^{1/3}\]
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
You then use polynomial or synthetic division to divide that expression.
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
The fraction is\[a^2ab+b^2\]so your expression will become,\[\sqrt[3]{a^2ab+b^2}\]
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
Hmm, it's a bit difficult to explain on this site. I'll see if I can find a link with a clip.
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
Here you go: http://www.khanacademy.org/video/polynomialdivision?playlist=ck12.org%20Algebra%201%20Examples
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
It's not a hard thing to do  you'll pick it up quickly.
 3 years ago

Brandon LamBest ResponseYou've already chosen the best response.0
can you tye wgat number I need division
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
Sorry, I'm sure what you want?
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
You still want me to do the division?
 3 years ago

Brandon LamBest ResponseYou've already chosen the best response.0
division like this: a+b:〖 a〗^3+ b^3
 3 years ago

Brandon LamBest ResponseYou've already chosen the best response.0
you just write eqution and I know how to division
 3 years ago

Brandon LamBest ResponseYou've already chosen the best response.0
I just want to know what number division by what number
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
The denominator appears on the LHS, the numerator on the RHS.
 3 years ago

KhaledyahyaBest ResponseYou've already chosen the best response.0
Can any of u help me how to draw the graph
 3 years ago

Brandon LamBest ResponseYou've already chosen the best response.0
thank, I can solve now
 3 years ago

lokisanBest ResponseYou've already chosen the best response.0
No probs. Become a fan :)
 3 years ago
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