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lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0Radicals are just expressions for powers, so you can use power laws to turn your orginal expression into:\[\left( \frac{a^3+b^3}{a+b} \right)^{1/3}\]

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0You then use polynomial or synthetic division to divide that expression.

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0The fraction is\[a^2ab+b^2\]so your expression will become,\[\sqrt[3]{a^2ab+b^2}\]

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0Hmm, it's a bit difficult to explain on this site. I'll see if I can find a link with a clip.

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0Here you go: http://www.khanacademy.org/video/polynomialdivision?playlist=ck12.org%20Algebra%201%20Examples

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0It's not a hard thing to do  you'll pick it up quickly.

Brandon Lam
 3 years ago
Best ResponseYou've already chosen the best response.0can you tye wgat number I need division

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0Sorry, I'm sure what you want?

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0You still want me to do the division?

Brandon Lam
 3 years ago
Best ResponseYou've already chosen the best response.0division like this: a+b:〖 a〗^3+ b^3

Brandon Lam
 3 years ago
Best ResponseYou've already chosen the best response.0you just write eqution and I know how to division

Brandon Lam
 3 years ago
Best ResponseYou've already chosen the best response.0I just want to know what number division by what number

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0The denominator appears on the LHS, the numerator on the RHS.

Khaledyahya
 3 years ago
Best ResponseYou've already chosen the best response.0Can any of u help me how to draw the graph

Brandon Lam
 3 years ago
Best ResponseYou've already chosen the best response.0thank, I can solve now

lokisan
 3 years ago
Best ResponseYou've already chosen the best response.0No probs. Become a fan :)
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