anonymous
  • anonymous
lim of (x^3-13x+12)/(x^3-14x+15) as x approaches 3 without using L hopital's rule. :( hope you can help me guys.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
dude none of them are going to help you
anonymous
  • anonymous
:( maybe you're right.
nowhereman
  • nowhereman
Don't be so pessimistic. Did you try actually dividing those polynomials as far as you can?

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anonymous
  • anonymous
you have to divide it so that when you plug x=3 , the result is not 0/0
anonymous
  • anonymous
i still get 0/0 guys
anonymous
  • anonymous
by using L hopital's rule i get 14/13. but the question must be solved w/o using it. :(
anonymous
  • anonymous
usually, there will be a common factor between the denominator and the numerator, but i can't factorize those polynomial
anonymous
  • anonymous
this problem sure is hard. xD
nowhereman
  • nowhereman
If a polynomial has a root "a", there is a factor (x-a) in it!
anonymous
  • anonymous
i don't get your point bro.
anonymous
  • anonymous
i got the common factor ! it's gonna be -> (x-3)(x^2 + 3x -4) / (x-3)(x^2+3x-5)
anonymous
  • anonymous
you can eliminate x-3, then plug x=3 you'll get -> (9+9-4)/(9+9-5) = 14/13
anonymous
  • anonymous
whoa! thanks din!!!
anonymous
  • anonymous
you're welcome btw, i got the common factor by using Horner's method
anonymous
  • anonymous
I'm not familiar with it. can you please give some background :D
anonymous
  • anonymous
i'll just google it. :)) thanks din for the info. ;)
anonymous
  • anonymous
:)
anonymous
  • anonymous
lol! it's just synthetic division :))
anonymous
  • anonymous
haha in my school we usually call it horner's method
anonymous
  • anonymous
The denominator and the numerator are both 0 when x = 3, what does that tell you?
anonymous
  • anonymous
it means that the function is in indeterminate form :)
anonymous
  • anonymous
obtaining 0/0 in a function doesn't that it has no limit. :)
anonymous
  • anonymous
what the answer in this question? please. I help me out 😉

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