anonymous
  • anonymous
At 1000 hours an aircraft starts from A to fly to B, a flight which will take 4 hours. At 1042 a second aircraft starts the same journey and will complete the flight in 2 hours 30 minutes. If the distance from A to B is 800 miles, at what time will the aircraft be the same distance from B?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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amistre64
  • amistre64
when the distance between the 2 planes = 0 then they are the same distance from pointB
amistre64
  • amistre64
800/4 is the speed of the 1st aircraft 800/(2.5) is the speed of the second aircraft..
amistre64
  • amistre64
200 mph and 320 mph sound about right...

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amistre64
  • amistre64
does 1042 means 42 minutes after 10?
anonymous
  • anonymous
yeah I got the speeds
anonymous
  • anonymous
thats right 45 mins after 10
amistre64
  • amistre64
ok, so if we convert 45 minutes into a fraction of an hour, we will be able to work with it better.... 3/4 or .75 of an hour....
anonymous
  • anonymous
42 mins* but thats where I got stuck
amistre64
  • amistre64
ok... 60/42 is a good enough fraction to work with :)
anonymous
  • anonymous
yeah got that
amistre64
  • amistre64
divide each by 3... 20/14....10/7.... 15/7 seems good... you agree?
amistre64
  • amistre64
10/7 seems good
anonymous
  • anonymous
yeah 10/7 looks ok
anonymous
  • anonymous
these are the options given: a 1110 hrs b 1124 hrs c 1142 hrs d 1152 hrs
amistre64
  • amistre64
lets make some equations then... 200x + 10/7 = D 320x = D does that make sense to you?
amistre64
  • amistre64
I think i missed it... we need to know hoe far the first plane has traveled and add that...not the hours...lol
amistre64
  • amistre64
200(10/7) is the "added" distance, or the advantage that the 1st plane has...
anonymous
  • anonymous
ermm .. Y would it be + 10/7. Dont get how the + comes into it
anonymous
  • anonymous
ok that makes sense
amistre64
  • amistre64
200x + 285.7 = D 320x = D where D is the equal distance flown .... hows that?
anonymous
  • anonymous
yeah that makes sense
amistre64
  • amistre64
makes better sense, but what doesnt make sense to me yet is that it is less than an hour, but the 1st plane has gone more than 200? gotta see where I missed that at :)
anonymous
  • anonymous
hmm ...
amistre64
  • amistre64
200(60/42) = 190.5 looks alot better, musta got it turned around in me head somewhere :)
anonymous
  • anonymous
I didnt get 190.5
amistre64
  • amistre64
7/10 should be our multiplier... 60 is the whole, 42 is the part; part/whole = percent.... .7
amistre64
  • amistre64
200(.7)= 140... that HAS to be it lol maybe
anonymous
  • anonymous
One way to consider it: Look at the time when only the first is flying; it is going to 200mph for 42 minutes, so will end up 140miles away from A. NEXT, look at the motion after they are both moving. If you apply a vector of -200mph to both planes, the one that set off first is effectively stationary, so you only need to consider how long it takes the second plane to 'catch up' the 140 mile head start at (320 - 200)mph = 120mph, which is just time = distance over speed. Add the initial 42 minutes and you're done.
amistre64
  • amistre64
200/60 tells us miles per minute; times 42 equals distance traved in 42 minutes...
amistre64
  • amistre64
200x+140 = 320x 140 = 320x - 200x 140 = 120x x = 140/120 = 14/12 = 7/6... 1 hour and 6/60 minutes.... if it agrees with Newtons :)
anonymous
  • anonymous
oh that make sense so it should be 200(42/60) = 140 (I.e the distances travelled by plane A)
amistre64
  • amistre64
Yep.... 1042 + 0106 = 1148...
anonymous
  • anonymous
but these are the options: a 1110 hrs b 1124 hrs c 1142 hrs d 1152 hrs
amistre64
  • amistre64
1 hour and 1/6 of another .... ack!! my math is off today...
amistre64
  • amistre64
1hour and 10 minutes... double check that :)
amistre64
  • amistre64
1042+0110 = 1152....
anonymous
  • anonymous
But yes, I agree. Time = 42 minutes + (140/120) minutes = 42 + (7/6) hours = the same as yours.
anonymous
  • anonymous
Ahh .. thanks you

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