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the answer for first is 0 . just need the steps.

you mean the following limits?

is the first one
\[\lim_{x \rightarrow 1}{x \over 1-x}?\]

nope

the its x^ 1/1-x

plz see the attachment its question number 2 -> 5th and 6th one

any answers / suggestions
?

yup. that's right
sorry for the confusion

x^(1/(1-x)) looks good

So you should apply the definition of a^b

well in l'hopital's rule u have to take drivatives

hmm..

there is a typo!! but the idea is still there.. does that make any sense to you?

i mean the equation is in 0 form right

what do you mean by 0 form?

why r u using ln in this

It's the way to finding the limit using l'hopital's rule.. this method is well known.

I am sure your instructor will use the same method to find the limit :P

^^
COOL :)

what about second question

What is the value that x goes to? And do you mean x^2 - ( (e^x) / x ) ?

x-> infinity , and yes ur right. it was my writing mistake. as before thanks

x^2 - ( (e^x) / x ) is right!

ok