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anonymous

  • 5 years ago

solve the polynomial equation. in order to obtain the first root, use synthetic division to test the possible rational roots. x^3+6x^2+21x+26=0

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  1. amistre64
    • 5 years ago
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    possible roots are what; factors of 26/factors of 1?

  2. anonymous
    • 5 years ago
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    yes

  3. amistre64
    • 5 years ago
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    1,26 ; 2, 13; cant think of any more :) make em +- of course

  4. amistre64
    • 5 years ago
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    2 | 1 6 21 26 0 2 16 ----------- 1 8 ... doesnt seem to be a root.....

  5. amistre64
    • 5 years ago
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    -2 | 1 6 21 26 0 -2 -8 -26 -------------- 1 4 13 0 .... x = -2 is a root i think

  6. amistre64
    • 5 years ago
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    (x+2)(x^2 +4x +13)

  7. amistre64
    • 5 years ago
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    thats all she wrote on that one, the quadratic doesnt touch the x axis so no more roots allowed

  8. amistre64
    • 5 years ago
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    do you agree? or wanna know how i did it?

  9. anonymous
    • 5 years ago
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    sorry.....I agree

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