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anonymous
 5 years ago
Hey  need some help deriving trig. identities from Euler's formula.
anonymous
 5 years ago
Hey  need some help deriving trig. identities from Euler's formula.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0what was eulers formula?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0e^(ix) = cosx + isinx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So would it then be true that e^(i2x)= (cosx + isinx)^2 as well as e^(i2x) = cos(2x) + isin(2x) ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So e^(i2x)=cos(2x)isin(2x)=(cos(x)isin(x))^2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The problem I have is that it seems that when I add e^(i2x)+e^(i2x), I get 2cos2x=2cos^2(x) ! Obviously I'm going wrong somewhere.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0cos(2x) = the real part of (cos(x)isin(x)^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Nevermind, I think I figured it out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Err the real part of (cos(x)+isin(x))^2
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