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anonymous
 5 years ago
The height of a ball after t seconds is given by h=80t16t^2. How long did it take the ball to hit the ground?
anonymous
 5 years ago
The height of a ball after t seconds is given by h=80t16t^2. How long did it take the ball to hit the ground?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0factor it out: 16t(5t)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dont know it doesnt say. i copied the question exactly

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0we know that anything times zero = 0; so either 16t = 0 or 5t =0

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0when t=0 that makes no sense, so it can be disregarded as a false positive; lets go with t=5 and see where that gets us

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we mulity 5 x 5= 25 then 25 x 16

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0h = 80(5)  16(5)2 0 = 400  16(25) 0 = 400  400 .... looking like a possibility

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i am lost if it is correct would the answer b 0 or 400

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0if the ball is dropped from a certain height, then t=0 makes no sense; but if we are starting the ball at ground level, and throwing it up, then maybe t=0 is an option

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Since it does not state that we "drop" the ball, itd be safe to include 0 id assume.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0at any rate; 5 seconds is what it takes after being "released" to hit the ground
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