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anonymous

  • 5 years ago

The height of a ball after t seconds is given by h=80t-16t^2. How long did it take the ball to hit the ground?

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  1. amistre64
    • 5 years ago
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    when does h=0?

  2. amistre64
    • 5 years ago
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    factor it out: 16t(5-t)

  3. anonymous
    • 5 years ago
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    dont know it doesnt say. i copied the question exactly

  4. amistre64
    • 5 years ago
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    we know that anything times zero = 0; so either 16t = 0 or 5-t =0

  5. amistre64
    • 5 years ago
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    when t=0 that makes no sense, so it can be disregarded as a false positive; lets go with t=5 and see where that gets us

  6. anonymous
    • 5 years ago
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    so we mulity 5 x 5= 25 then 25 x 16

  7. amistre64
    • 5 years ago
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    h = 80(5) - 16(5)2 0 = 400 - 16(25) 0 = 400 - 400 .... looking like a possibility

  8. anonymous
    • 5 years ago
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    sorry i am lost if it is correct would the answer b 0 or 400

  9. amistre64
    • 5 years ago
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    if the ball is dropped from a certain height, then t=0 makes no sense; but if we are starting the ball at ground level, and throwing it up, then maybe t=0 is an option

  10. anonymous
    • 5 years ago
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    ok i get that

  11. amistre64
    • 5 years ago
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    Since it does not state that we "drop" the ball, itd be safe to include 0 id assume.

  12. amistre64
    • 5 years ago
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    at any rate; 5 seconds is what it takes after being "released" to hit the ground

  13. anonymous
    • 5 years ago
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    k thank you

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