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anonymous

  • 5 years ago

I am working on solving the system of equations by graphing. I am having some problems so I hope someone can show me an easier way of doing this. This is what I have x-3y=-3 & x+3y=9.

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  1. anonymous
    • 5 years ago
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    solve each equation for one of the two variables you have as: x-3y=-3 will be x=3y-3. (1) x+3y=9 will be x=9-xy (2) find any two points in each function, and connect them with a line. the intersection point is your solution.. I hope that would help

  2. anonymous
    • 5 years ago
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    the second equation is x=9-3y.. sorry for the typo!!

  3. anonymous
    • 5 years ago
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    That is were I am running into problems. I think I am getting the first one. Here is what I have so far. 1st equation: x-3y=-3. I got y=1/3x-3/3(1) x=3 and y=1 2nd equation: x+3y=9. I got y=-1/3x+9/3(3) x=9 and y=3 The problem I am having is figuring out the second point to draw the line.

  4. anonymous
    • 5 years ago
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    Can you show me something that will work on all the equations?

  5. anonymous
    • 5 years ago
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    take any value of x and find the corespondent value of y.. this is a new point

  6. anonymous
    • 5 years ago
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    so just pick any number for x to solvethe equation?

  7. anonymous
    • 5 years ago
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    well is it okay if we work in my equations.. it looks much simpler. you know how I got them anyway?

  8. anonymous
    • 5 years ago
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    so is my work right so far?

  9. anonymous
    • 5 years ago
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    I didn't check it.. let me

  10. anonymous
    • 5 years ago
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    yes please do.

  11. anonymous
    • 5 years ago
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    hmm I don't think you're following the right method.. you're asked to solve them by graphing.. so find any two points in the line and coonnect them. do this to both lines, just find where they intersect and you're done.

  12. anonymous
    • 5 years ago
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    to get points.. just substitute any value for x, get the corespondent value of y.. this is a point

  13. anonymous
    • 5 years ago
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    Ok but I never worked i you way. They are showing us theway I put I wrote it. So now I am kind of confused.

  14. anonymous
    • 5 years ago
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    should be worked it your way.

  15. anonymous
    • 5 years ago
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    watch this.. it may help

  16. anonymous
    • 5 years ago
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    I will do your problem the way that's usually done by steps: 1) solve both equations for y: 1st equation: \[y={1 \over 3}x+1\rightarrow (1)\] 2nd equation: \[y={-1 \over 3}x+3 \rightarrow(2)\]

  17. anonymous
    • 5 years ago
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    please check my steps!! :)

  18. anonymous
    • 5 years ago
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    2) find two points for each equation (intersection points are usually preferred): 1st for equation (1): \[x=0 \implies y=1, x=3 \implies y=2\] so we have the two points in the first line which are (0,1) and (3,2)

  19. anonymous
    • 5 years ago
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    for equation (2): \[x=0 \implies y=3, x=3 \implies y=2\] we have two points in the second line, which are (0,3) and (3,2)

  20. anonymous
    • 5 years ago
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    3) draw the line of each equation by connecting the two pints in each one

  21. anonymous
    • 5 years ago
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    4) find the point they intersect at (x,y), this point is the solution of the linear system!! :)

  22. anonymous
    • 5 years ago
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    I guess that was confusing to you, but you should have said thanks :P

  23. anonymous
    • 5 years ago
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    sorry had to go help the wife fix supper. Will look it over closely and use to try my next problem and see if I get it right. Thank you very much for your help.

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