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anonymous
 5 years ago
An experiment consists of 48 binomial trials, each having probability 3/4 of success. Use an approximating normal curve to estimate the following probabilities.
(a) between 35 and 39 successes, inclusive.
anonymous
 5 years ago
An experiment consists of 48 binomial trials, each having probability 3/4 of success. Use an approximating normal curve to estimate the following probabilities. (a) between 35 and 39 successes, inclusive.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use the fact that when np>5, then a normal approximation with mean np and std. dev with sqrt(np(1p)) allows you to solve this. So, the normal curve with mean 36 and std. dev. of 3 will be what you need to use

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yea i found all those already. n= 48 p = .75 mean = 36 st. dev. = 3 I tried 36.536/3 but the answer I got was wrong.... I don't know what I'm doing wrong.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oops not 36.536 that's for another question. Ignore the bottom part.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I guess I should say, you should then use 35<x<39 and then find the area between the z curves (xu)(sigma)...don't know sigma symbol. sorry

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I thought I would do 35  36/3 and 3936/3 but that's wrong too. I'm not sure what I'm doing.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.03536=1, then divide by 3 is 1/3 3936=3 then divide by 3 is 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0those are the zvalues you want to use...Is that still giving you the wrong answer?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0should be around 47% or so yes?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know I got those answers, but when I subtracted the area of those...it was still wrong. .8413.3821 = .4592

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is the answer? maybe they want you to use a continuity correction

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know the answer, they won't give it to me. I have to keep on trying until I get it right.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm, that is strange. if you get really desperate you could always sum up the bernoulli cases 35, 36, 37, 38, and 39 if you have access to technology that computes combinations

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes I have a TI83. How would I do that? 35C0 + 36C.....those?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.048C35*p^35*(1p)^13+48C36*p^36*(1p)^12+...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you use continuity corrections, then you get this answer. I had forgot to do that. when you go from a discrete to a continuous probability, this can sometimes greatly affect your answer, especially when bounded on both sides

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0.5795 is incorrect too... Thanks for trying to help me though!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0man, that is crazy,I'm a stats man and this is embarrassing ;( is it a computer system? then maybe it is rejecting due to rounding, you think?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0with continuity correction i got around .57. other than that, I got nothing...though this problem will bother me for a while!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I tried .5795, .57, and .58. None of them worked. I have been working on this problem for a while now haha so it's okay. Thank you for trying to help me with this though! I have another question though if you still want to help me? The third part of the question asks me to find "more than 36 successes" I did 36.536 / 3 which = .1666, so the area would be .5636 but that's incorrect. What am I doing wrong?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0greater than means you have to take 1minus the value from the zscore

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the ztable gives you less than percentage, not greater than percentage

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which would make it .4364 ..... which is still wrong...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I feel like I'm making a silly mistake.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hmm, I just don't know why it isn't working out. that is definitely what you are supposed to do when you have a bernoulli problem and are using the normal curve to approximate it. I really don't know what to tell ya. did you try this one without the cont. correction? it would be 50%. If that doesn't work then I really have no idea:(

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0actually, more than 36 without cont.correction would be 37, which would give 1/3 and then 1that would be around .367...I have no clue at this point though. wish you luck

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0:( Okay well thank you for helping me!
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