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anonymous

  • 5 years ago

f'(x) = 2x - e^x = 0

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  1. anonymous
    • 5 years ago
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    what do you want to find?

  2. anonymous
    • 5 years ago
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    to solve for x?

  3. anonymous
    • 5 years ago
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    i want to find x

  4. anonymous
    • 5 years ago
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    I believe this is just part of the whole question, what actually are you working on?

  5. anonymous
    • 5 years ago
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    Finding the absolute maximum and minimum values of f(x) = 2x - e^x on [0,1]. i'm stuck

  6. anonymous
    • 5 years ago
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    ok, good, then the information given above is not correct f(x) = 2x - e^x f'(x) = 2 - e^x

  7. anonymous
    • 5 years ago
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    You can solve your f'(x) = 0 easily now

  8. anonymous
    • 5 years ago
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    i see that e^x should be 2 but wat about x

  9. anonymous
    • 5 years ago
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    e^x = 2 Take log on both sides: x = log(2), log = natural logarithm

  10. anonymous
    • 5 years ago
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    ok

  11. anonymous
    • 5 years ago
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    I believe you know how to determine the absolute extrema

  12. anonymous
    • 5 years ago
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    plugging that into the fucntion with the endpoint values and determining the max and min

  13. anonymous
    • 5 years ago
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    very good, yup

  14. anonymous
    • 5 years ago
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    thx for ur help

  15. anonymous
    • 5 years ago
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    you're welcome

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spraguer (Moderator)
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