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anonymous
 5 years ago
f'(x) = 2x  e^x = 0
anonymous
 5 years ago
f'(x) = 2x  e^x = 0

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do you want to find?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I believe this is just part of the whole question, what actually are you working on?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Finding the absolute maximum and minimum values of f(x) = 2x  e^x on [0,1]. i'm stuck

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok, good, then the information given above is not correct f(x) = 2x  e^x f'(x) = 2  e^x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You can solve your f'(x) = 0 easily now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i see that e^x should be 2 but wat about x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0e^x = 2 Take log on both sides: x = log(2), log = natural logarithm

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I believe you know how to determine the absolute extrema

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0plugging that into the fucntion with the endpoint values and determining the max and min
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