anonymous
  • anonymous
f'(x) = 2x - e^x = 0
Mathematics
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anonymous
  • anonymous
f'(x) = 2x - e^x = 0
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
what do you want to find?
anonymous
  • anonymous
to solve for x?
anonymous
  • anonymous
i want to find x

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anonymous
  • anonymous
I believe this is just part of the whole question, what actually are you working on?
anonymous
  • anonymous
Finding the absolute maximum and minimum values of f(x) = 2x - e^x on [0,1]. i'm stuck
anonymous
  • anonymous
ok, good, then the information given above is not correct f(x) = 2x - e^x f'(x) = 2 - e^x
anonymous
  • anonymous
You can solve your f'(x) = 0 easily now
anonymous
  • anonymous
i see that e^x should be 2 but wat about x
anonymous
  • anonymous
e^x = 2 Take log on both sides: x = log(2), log = natural logarithm
anonymous
  • anonymous
ok
anonymous
  • anonymous
I believe you know how to determine the absolute extrema
anonymous
  • anonymous
plugging that into the fucntion with the endpoint values and determining the max and min
anonymous
  • anonymous
very good, yup
anonymous
  • anonymous
thx for ur help
anonymous
  • anonymous
you're welcome

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