anonymous
  • anonymous
2sin^2x-sinx-1=0, solve for x
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
factor this thinking about the entire sinx as the variable, then set each factor to zero and solve from there
anonymous
  • anonymous
Can you factor 2x^2 - x - 1 = 0
anonymous
  • anonymous
yeah, put 2x in one parentheses and x in the other and try factors of 1...not much choice of course

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anonymous
  • anonymous
Just making sure you understood what jpick said
anonymous
  • anonymous
(sinx-1)(2sinx+1)=0 sinx=1 and 2sinx=-1 sinx = 1 and sinx = -1/2 x = sinx^-1(1) and x = sinx^-1(-1/2) x= \[x=\pi/2 and x=-\pi/6\]
anonymous
  • anonymous
x=π/2 and x=−π/6

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