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anonymous
 5 years ago
Find all the critical points of the function M(x,y) = 2x^2  x^3 + 2xy^3  2y.
anonymous
 5 years ago
Find all the critical points of the function M(x,y) = 2x^2  x^3 + 2xy^3  2y.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I found the y value one critical point to be y=1/3x^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm having trouble finding the x value for this particular point and I'm not sure if there are any other critical points

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got y^2=1/3x for the DM/dy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0umm, as far as solving this, umm, the algebra is looking nasty. substitute this into the DM/dx and try to solve for actual numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whoops, I messed up the derivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0even after i corrected my derivative, I still have a lot of nasty algebra...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know its pretty gross.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you get anything like that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I got 6yx^2  2=0 and I can't get the right x value when solving

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get 6yx^2 2...was that your DM/dy?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0from this I got the x value \[\sqrt{1/3x^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0DM/dy I got 6xy^22 as the y was cubed in the original problem, or is that a typo?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OH whoops. that's what I got. I meant to square the y not the x. you're right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I will try some factors then, but I don't see any off hand that work immediately.
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