Can Someone Please Help Me with some Geometry??

- anonymous

Can Someone Please Help Me with some Geometry??

- chestercat

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- anonymous

For these 3 pictures.. i need to find the surface area

##### 3 Attachments

- anonymous

the first one is composed of
2 triangles: 4x5 + 4x5 = 40m
3 rectangles: 4x14 + 5x14 + \[14\times \sqrt{4^{2} + 5^{2}}\]
and you add all of them up

- anonymous

so the first one would be 89.64?

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- radar

Area of triangle is BH/2, in this figure that equals (4 x 5)/2=20/2=10 sq M, but their are two so the surface area of the triangular portion would be 20 sq meter.

- anonymous

for the first one i got 2(20)+Ph.. i need to find out what the perimeter is

- radar

The suface of the sides are as indicated by tacolover. 5x14= 70 sq M for one side. 4x14=56 sqM for another side and 14 x sq rt(16+25)
\[\sqrt{41}\times14\]

- anonymous

im totally lost... the formula i have to use is 2B+Ph

- radar

Final answer is: 10+10+70+56+89.6=235sq M

- anonymous

so that would be for the first one?

- radar

That will work too

- radar

yes as long as you remember that the B is a triangle and their are two of them.

- radar

P is perimeter and you must user all three sides.

- radar

You want to look at the next figure?

- anonymous

yeah.. so far for the next one i got 2(28)+Ph

- radar

It is a cylinder or like a can. Too find the total surface area you calculate the area of the ends which are circles (don't forget their are two of them. Then the body is actually a rectangle which has one side equal to the circumference of the circle times the height.

- radar

Do you agree?

- anonymous

yeah.. sorry for some reason i put up the wrong picture.. but i need help with that one to

- anonymous

so id use 2*pi*r^2+2*pi*r*h

- radar

Do you know how calculate the area of circle whose diameter is 8cm or radius would be 1/2 of that or 4 cm.??

- radar

The area of the ends would be as you have but it would be like 2(2*pi*r^2).
Then the can (not the ends) would be h*C
8*piD=8*pi*8

- radar

I am sorry I got the area wrong for the ends. The formula is pi*r^2 so the ends would be 2(pi*r^2) that is for both ends

- anonymous

so for r would it be half the diameter (8).. so 2(3.14*4^2)

- radar

Yes that gives you the area for the ends of the cylinder. both

- anonymous

so 100.48

- radar

Let me check yes for the ends. Now this must be added to the surface area of the body of the can pi*D*h

- anonymous

so 3.14*8*12=301.44

- radar

Right now add the end area to your 301.44

- anonymous

than i would add 100.48+301.44=401.92

- radar

Yes that would give you the total surface area of the can, I forgot that the heigth was 12 and put 8 but you caught it!

- radar

and that is in sq cm

- anonymous

okay

- radar

Do you need any help on the 3rd figure.

- anonymous

no but will you check this one for me

##### 1 Attachment

- anonymous

i got 326.25m^2

- radar

Does it have a bottom and a top? It is hard to tell from the drawing!

- anonymous

yea

- radar

I used calculator and got 326.73, so I would say you used the correct procedure and don't forget what the units are.......sq M

- anonymous

ok thank you

- anonymous

can you also check this one.. i got 254.34 ft^2

##### 1 Attachment

- radar

I agree with your answer of 254.34 sq ft.

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