## anonymous 5 years ago Find the values of x that give local extrema for the function f(x) = x^3 – 3x

A function $f(x)$has local extrema inside the domain at those numbers, x, such that$f'(x)=0$Here,$f'(x)=3x^2-3$and upon setting to zero$3x^2-3=0 \rightarrow x^2=1 \rightarrow x=\pm 1$