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anonymous
 5 years ago
A rectangular plot of land will be bounded on one side by a river. On the other three sides, it will be bounded by a fence. With 500m of fence to use, what is the largest area you can enclose, and what are its dimensions? (I'm having trouble with this one)
anonymous
 5 years ago
A rectangular plot of land will be bounded on one side by a river. On the other three sides, it will be bounded by a fence. With 500m of fence to use, what is the largest area you can enclose, and what are its dimensions? (I'm having trouble with this one)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I do know the more closely it becomes a square the larger the area you have. Let me think on this and get back to you shortly.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A = Length * width A = lw 500 = 2w + l solving this for l you get l = 500  2w substitute that back into the A=lw A = (500  2w)w distribute A = 500w  2w^2 The maximum can be found at the vertex which you find the w value by b/2a = 500/2(2) = w = 125 so I think the width = 125 and the length would be 250

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02x + y = 500 y = 5002x area = xy A = x(5002x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I would find the maximum by completing the square, but I'm a badass.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0A = 500x 2x^2 dA = 500 4x x = 500/4 = 250/2 = 125

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you guys for your help...You are all awesome =D

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = 5002x y = 500  2(125) y = 500  250 y = 250

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0blext was right...and first :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But you did it the "cool" way
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