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anonymous
 5 years ago
A frog leaps from a stump 4 feet high and lands 6 feet from teh base of the stump. we can consider the initial position of the frog to be (0,4) and its landing to be (6,0).
the height of the frog in feet is given by the following equation: 1/3x^2+4/3x+4
1. what is the horizontal distance (x) from the base of the stump when the frog reached maximum height?
2. what was the maximum height
anonymous
 5 years ago
A frog leaps from a stump 4 feet high and lands 6 feet from teh base of the stump. we can consider the initial position of the frog to be (0,4) and its landing to be (6,0). the height of the frog in feet is given by the following equation: 1/3x^2+4/3x+4 1. what is the horizontal distance (x) from the base of the stump when the frog reached maximum height? 2. what was the maximum height

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The maximum height is found at the vertex of the parabola. You have a parabola when you have an x^2 term as the highest degree. The vertex is found at b/2a this happen to be the horizontal distance. what would b/2a be?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Are you in Algebra or Calculus? This is an algebraic way of doing it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK.. so let's do it this way. a = 1/3 b = 4/3 b/2a = 4/3 over 2/3 ok so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0When you divide by a fraction, you multiply by the reciprocal. 4/3 * 3/2 = 12/6 = 2 so x = 2 that is how far away from the stump you are when the the frog is at it's maximum

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so the vetex is 2 and thats the horizontal distance?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f f f f f s f f  fground ^ x = 2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does my picture make sense... kind of dumb I know

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The x value of the vertex is 2 and that is the horizontal distance, now we need to find how high it is at x = 2 Substitute 2 into your equation and find y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y = 5.3 I think... (1/3)*4 + (4/3)*2 +4 4/3 + 8/3 + 4 4/3 + 4 5 1/3 Notice the vertex (which is the highest point) has coordinates (2,5.3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how would u sketch a graph of this problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use your xy coordinate graph paper. put a dot on (0,4) that is the frog. Put a dot on (6,0) that is where the frog lands Put a dot on (2,5.3) that is the highest point. Draw an arc "like throwing a ball up in the air" to the highest point and then down to the (6,0) point. Like a ball would look like if you were throwing it.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank u i thought it would be an arc
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