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The maximum height is found at the vertex of the parabola. You have a parabola when you have an x^2 term as the highest degree. The vertex is found at -b/2a this happen to be the horizontal distance. what would -b/2a be?
Are you in Algebra or Calculus? This is an algebraic way of doing it.
OK.. so let's do it this way. a = -1/3 b = 4/3 -b/2a = -4/3 over -2/3 ok so far?
ok got ya
When you divide by a fraction, you multiply by the reciprocal. -4/3 * -3/2 = 12/6 = 2 so x = 2 that is how far away from the stump you are when the the frog is at it's maximum
so the vetex is 2 and thats the horizontal distance?
f f f f f s f f --------- f-------------ground ^ x = 2
Does my picture make sense... kind of dumb I know
no that really helps
The x value of the vertex is 2 and that is the horizontal distance, now we need to find how high it is at x = 2 Substitute 2 into your equation and find y
or is it y=8
y = 5.3 I think... (-1/3)*4 + (4/3)*2 +4 -4/3 + 8/3 + 4 4/3 + 4 5 1/3 Notice the vertex (which is the highest point) has coordinates (2,5.3)
ok think i got ya
ok think i got ya
how would u sketch a graph of this problem
Use your xy coordinate graph paper. put a dot on (0,4) that is the frog. Put a dot on (6,0) that is where the frog lands Put a dot on (2,5.3) that is the highest point. Draw an arc "like throwing a ball up in the air" to the highest point and then down to the (6,0) point. Like a ball would look like if you were throwing it.
ok thank u i thought it would be an arc