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Distrubute the factors and multiply it out. Then simplify. Treat the inequality just as you would an equal side. The only tricky thing to remember is if you divide by a negative you have to change which way the inequality goes.
is the equation correct as stated?
Do you know how to do the distribution step?
-36x(x+4) > 4x - 16 - 3x -36x^2 - 144x > x-16 is correct?
no i dont not very good at algebra and to u amistre i think so
lets figure out what I did :) lets start with an easy example... 3(8) = 24 right?
then: 3(6+2) should also equal 24 right?
then this should also work for us: 3(6) + 3(2) = 24 18 + 6 = 24 24 = 24 .... do you see that? its called the distributive property and it allows us to "distribute" the 3 thru the (6+2) to get the answer.
oh ok i understand now
2(2x-8) distribute this for me then :)
very good :)
-7(x+4) how about this one?
excellent work..... see how easy that is :)
yes i do
that left side has one more "distribution" to take care of: 9x(-7x-28) is what? I know you can do this...
look over your "multiplication" work again and try that again.... 9x(-7x) +9x(-28) ....
wait i meant -63x-252
i see what mistake i made
very good, but remember to include the "x". x(x) = x^2 ; which means x squared.
-63x^2 -252x ..... ok?
that is correct.... -63x^2 -252x < 4x -16 -3x is what we are up to now.... do you know what we should do now?
we can simplify this to some extent yes, we can "combine" like terms..
-63^2 -252x < 4x-3x -16 -63x^2 -252x < x -16 Do you know how to move things from one side to the other? Its important to be able to do this while keeping the balance between them the same.... does that make sense?
yes it makes sense i think i do how to move one side to the the other
let me give you an easy example to remind you: 10 < 15 right? then 1+2+3+4 < 4+5+6 right?
to keep everything in balance...whatever we "add" or "remove" from one side has to be done to the other.... right? lets subtract "4" from each side 1+2+3+4 -4 < 4+5+6 -4 1+2+3 < 5+6 ; 6>11
that make sense
i flipped my sign around didnt i....
its these fat fingers and this tiny little keyboard :)
lol its ok i do that to
-63x^2 -252x < x -16 lets make the lefthand side = 0, to do that we need to "add" their value to both sides
-63x^2 [+63x^2] -252x [+252x] < [+63x^2] +x [+252x]-16
0< 63x^2 +253x -16 is what we get right?
yes thats what i got
now comes the hard part, because it gets a little on the "advanced" side of things for this one..... but we can use a formula called the "quadratic" formula to find the values for "x" that make this equal to zero... wanna try it out?
ok.... notive that we have numbers in front of all of our "terms". they are 63, 253, and -16. we want to use these in our quadratic formula....
-253 + sqrt(253^2 - (4)(-16)(63)) ------------------------------ 2(63) this aint gonna be pretty :)
is sqrt is square rIght?
yes, sqrt() is what I use to indicate the square root "umbrella" and everything inside of the () is what is under the "umbrella".
where ever did you get this inequality at? its almost a nightmare :)
its on a study guide but i have to go my computer is missing up thanxs for the help