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anonymous
 5 years ago
For a halfgallon (1892.7 cubic cm) of milk, the bottom of the container costs three times as the sides, while the top of the container costs 5 times as much as the sides. Assuming a square base to a rectangular carton (i.e. don't worry about the oddly shaped top), find the dimensions that minimize the cost of the container. After you solve the problem, check how closely your findings match the actual dimensions of a halfgallon carton of milk.
anonymous
 5 years ago
For a halfgallon (1892.7 cubic cm) of milk, the bottom of the container costs three times as the sides, while the top of the container costs 5 times as much as the sides. Assuming a square base to a rectangular carton (i.e. don't worry about the oddly shaped top), find the dimensions that minimize the cost of the container. After you solve the problem, check how closely your findings match the actual dimensions of a halfgallon carton of milk.

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0Volume = x^2(h) 1892.7 = x^2(h) h = 1892.7/x^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0is it 5 times as much as all the sides combined? or 5 times as much as 1 side?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Cost = Top + Bottom + Sides C = 5S + 3S + S

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0C = 9S S = xh C = 9xh C = (1892.9/x^2)(9x)
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