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anonymous

  • 5 years ago

y'' for y= (x^2+9)^4

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  1. anonymous
    • 5 years ago
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    \[8(x^2+9)^3+48x(x^2+9)^2\]

  2. anonymous
    • 5 years ago
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    awesome thank you

  3. anonymous
    • 5 years ago
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    could you show me y' for this so i can see how you got y''

  4. anonymous
    • 5 years ago
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    \[8x(x^2+9)^3\]

  5. anonymous
    • 5 years ago
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    thank you

  6. anonymous
    • 5 years ago
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    No Problem

  7. anonymous
    • 5 years ago
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    could you help me on another?

  8. anonymous
    • 5 years ago
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    Sure

  9. anonymous
    • 5 years ago
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    y'' for y= ln x/x^2

  10. anonymous
    • 5 years ago
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    I am horrible when it come to ln in problems

  11. anonymous
    • 5 years ago
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    \[-3x^(-4)+6lnx(x^(-4))+4x^(-4)\]

  12. anonymous
    • 5 years ago
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    ooops

  13. anonymous
    • 5 years ago
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    ha ha ha

  14. anonymous
    • 5 years ago
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    -3x^(-4)+6x^(-4)lnx+4x^(-4)

  15. anonymous
    • 5 years ago
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    could you show me how to do this?

  16. anonymous
    • 5 years ago
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    \[y=lnx(x^{-2})\] Then you use product rule

  17. anonymous
    • 5 years ago
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    okay..so then thats how you got the final answer

  18. anonymous
    • 5 years ago
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    y' = x^(-3)-2x^(-3)lnx

  19. anonymous
    • 5 years ago
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    and then you differentiate it again? do u know how to do that?

  20. anonymous
    • 5 years ago
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    yes then you get....

  21. anonymous
    • 5 years ago
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    -3x^(-4)+6x^(-4)lnx+4x^(-4)

  22. anonymous
    • 5 years ago
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    -3x^-4 + 6x^-4 lnx ?

  23. anonymous
    • 5 years ago
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    remember to use product rule for x^(-3)lnx

  24. anonymous
    • 5 years ago
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    where are you getting the last part?

  25. anonymous
    • 5 years ago
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    you forgot to use product rule for lnx(x^(-3))

  26. anonymous
    • 5 years ago
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    oh okay now im with you. thanks

  27. anonymous
    • 5 years ago
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    welcome

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