x+2 / x^2 -9 + x-3/x^2-2x-3 = 2x-3/ x^2+4x+3

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x+2 / x^2 -9 + x-3/x^2-2x-3 = 2x-3/ x^2+4x+3

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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what about it?
algebra , i dont know how to solve it.
kathyworld, it is not clear how the equation is formed. Can you please put in some brackets or parentheses to make the equation better?

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[ x+2 / x^2 -9] + [x-3/x^2-2x-3] = 2x-3/ x^2+4x+3
^ = power
I assume it looks like this: [(x+2 )/( x^2 -9)] + [(x-3)/(x^2-2x-3)] = (2x-3)/ (x^2+4x+3)
yes perfect :)
ok, thanks
i just dont understand how to solve it
[(x+2) / (x-3)(x+3)] + [(x-3) / (x-3)(x+1)] = (2x-3)/(x+3)(x+1)
is that the answer ?
[(x+2 )/( x^2 -9)] + [(x-3)/(x^2-2x-3)] = (2x-3)/ (x^2+4x+3) [(x+2 )/{( x-3)(x+3)}] + [(x-3)/{(x-3)(x+1)}] = (2x-3)/ {(x+3)(x+1)} So the monomials appear in the denominator are x-3, x+3 and x+1. Make all the fractions have the same denominator: [(x+2 )/{( x-3)(x+3)}] + [(x-3)/{(x-3)(x+1)}] = (2x-3)/ {(x+3)(x+1)} [{(x+2 )(x+1)}/{( x-3)(x+3)(x+1)}] + [{(x-3)(x+3)}/{(x-3)(x+1)(x+3)}] = {(2x-3)(x-1)}/ {(x+3)(x+1)(x-1)} So the numerator we have (forget for a while the denominator) (x+2)(x+1) + (x-3)(x+3) = (2x-3)(x-1) (x^2 + 3x +2) + (x^2 - 9) = 2x^2 - 5x +3 8x = 10 x = 5/4
wow you did the whole thing... I would've let vic23 do the basic algebric manipulations...
THANK YOU VERY MUCH SKLEE ! :)
Ya, I should leave some part for kathy to complete it ^_^
sorry vic23 is not the guy who asked the question. My apologies. Let me correct myself. I would've let kathyworld09 do the basic algebric manipulations
you're welcome kathy. Hope you learn something and understand it. I am sure you can do it next time :)
so its not fully completed ?
kathy, i have given the complete solution. :)
You should learn and understand how it is done, so that you can do it again in other problem next time
oh thank you , i just am having difficulty in a similar problem though

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