sinx/1-cosx+sinx/1+cosx=cscx

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

sinx/1-cosx+sinx/1+cosx=cscx

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

sinx/1-cosx+sinx/1+cosx=cscx
is it \[{\sin x \over 1-\cos x}+{\sin x \over 1+\cos x}=\csc x \]?
yes

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[={\sin x(1+\cos x)+\sin x (1-\cos x) \over 1-\cos^2 x}\] \[={ \sin x (1+\cos x+1 -\cos x) \over \sin^2 x}\] \[={2 \over \sin x}=2\csc x\]
are you sure the right hand side of the equation is cscx? because it should be 2 cscx!! assuming the question is asking to prove the identity.
i also got 2cscx . are you asked to prove the equation? if so, the equation can't be proved because it's wrong
no your right i miss type it thank you!
no problem
tan^2x=sec^2x-sin^2x-cos^2x ok its the same thing
this is an easy one.. \[=\sec^2 x-(\sin^2 x+\cos^2 x)= \sec^2 x-1 = \tan^2 x\] so you have both sides of the equation equal
tan^2x = sec^2x - (sin^2x + cos^2x) tan^2x = sec^2x - 1 tan^2x = (1/cos^2x) -1 tan^2x = (1-cos^x)/cos^2x tan^2x = sin^2x/cos^2x
sinx/cosx = tanx so -> sin^2x/cos^2x will be equal to tan^2x
sec^4x-tan^4x=sec^2x+tan^2x last one in this group
\[\sec^4 x-\tan^4 x=(\sec^2 x+\tan^2 x)(\sec^2 x- \tan^2 x)\] since sec^2-tan^2x=1, \[=\sec^2 x+\tan^2x\]
a fire is sighted due west of lookout A. the bearing of the fire from lookout B, 12.9 miles due south of A, is N 30^o 36' W. How far is the fire from B

Not the answer you are looking for?

Search for more explanations.

Ask your own question