anonymous
  • anonymous
use a double- angle identity to find the exact value sin22.5^ocos22.5^o
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
why I am still at 19 fans, after spending the last 5 hours working my *** out?
anonymous
  • anonymous
if you help me with this i will become a fan
anonymous
  • anonymous
ok, one min

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anonymous
  • anonymous
the double angle identities are as follows: \[\cos (A - B) = (\cos A)(\cos B) + (\sin A)(\sin B) \] \[\cos (A + B) = (\cos A)\cos B - (\sin A)\sin B \] \[\sin (A + B) = (\sin A)(\cos B) + (\cos A)(\sin B) \] \[\sin (A - B) = (\sin A)(\cos B) - (\cos A)(\sin B) \] alright andy :) you can lead from here ^_^
anonymous
  • anonymous
hmm, am I mixing it all up with the double angle identities? those are the sin and cos indentities , hmm, please correct me if I'm wrong ^_^
anonymous
  • anonymous
double angle identities go like this, egzample: sin(2x)=2sinxcosx
nowhereman
  • nowhereman
That is just the above with setting A=B
anonymous
  • anonymous
no the identities are sin2A=2sineAcosA cos2A-cos^2A-sin^2A =1-2sin^2A =2cosA-1
anonymous
  • anonymous
or right lol , thank you, alright angoo, give it a try ^_^
anonymous
  • anonymous
ok I am bad at this, I guess I must have skipped school the day this stuff was tought
anonymous
  • anonymous
give it a try :)
anonymous
  • anonymous
yeah same here
anonymous
  • anonymous
nah, stary, you go ahead, I dont get this stuff yet
anonymous
  • anonymous
ask your beloved google lol
anonymous
  • anonymous
well, Google can give me examples, and explanations, and I can learn from them, but it would take too much time... so just go ahead and do it mimi
anonymous
  • anonymous
this is my new signature btw: ▓▒░╔ᴧᴨᴅᴙiᴜs╖░▒▓
anonymous
  • anonymous
LOL
anonymous
  • anonymous
alright LoveL , let me get this clear : you want to find the answer of : sin(22.5)cos(22.5)? or do you want to find the exact angle for sin(22.5)=? or cos(22.5)=? ^_^ lol, it's filled with mystery, but I like it :)
nowhereman
  • nowhereman
I will show you, first of all: \[\sin (22.5^\circ)\cos(22.5^\circ) = \sin(\frac{180^\circ}{8})\cos(\frac{180^\circ}{8}) = \sin(\frac{π}{8})\cos(\frac π 8)\]
anonymous
  • anonymous
nvm, follow up with nowhereman ^_^ he'll lead you through.
anonymous
  • anonymous
so, loveinglife, do you feel happy today? because I do, but I could become even more happy if you gift me a fan =D In that case, I will give you a fan too, so you become a lifesaver, and I become a superstar, a clear winwin =D
anonymous
  • anonymous
LOL, and you're still on it
anonymous
  • anonymous
@BecomeMyFan im your fan now. thank you for trying
nowhereman
  • nowhereman
Then \[\sin(\frac π 8)\cos(\frac π 8) = \frac 1 2 \cdot \left(2\sin(\frac π 8)\cos(\frac π 8)\right)\] Thus by applying that double arc formula on the inner part (in reverse direction if you want) you get \[=\frac 1 2 \sin(2\frac π 8) = \frac 1 2\sin(\frac π 4) = \frac 1 4 \sqrt 2\]
anonymous
  • anonymous
Oh my god your awesome. thank you soo much you just saved my trig grade
nowhereman
  • nowhereman
You're welcome :-D
anonymous
  • anonymous
love, are you in highschool?
anonymous
  • anonymous
or in college
anonymous
  • anonymous
?
anonymous
  • anonymous
because if you are doing this stuff in high school, I must have skipped ALOT of it
anonymous
  • anonymous
im saddly in college and i thought i was good in math till i got here
anonymous
  • anonymous
:)
anonymous
  • anonymous
why am I still a mear star?
anonymous
  • anonymous
I wanna be a superstar
anonymous
  • anonymous
it was supposed to rhyme
anonymous
  • anonymous
=D
anonymous
  • anonymous
sorry cant help you there but im done, but i will probably be back at some point
anonymous
  • anonymous
it is part of a poem I am writting about OpenStudy
anonymous
  • anonymous
=)
anonymous
  • anonymous
you write poems?

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