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anonymous
 5 years ago
can someone help me out on some calculus?
anonymous
 5 years ago
can someone help me out on some calculus?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what's your question ^_^?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im doing second derivatives and graphing and i am totally lost

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how come? which part are you lost in?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0something that has to do with infelction points? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this problem..summarize the pertinent information obtained by applying the graphing strategy and sketch the graph of y=f(x) f(x)=(x2)(x^24x8)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have no idea what to do. or where to start

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0does it have to do with graphing f'(x)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's in the lesson of second deriviatives and graphing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it has to do with inflection points :)because when you find the second derivative, you are finding, at the same time, the inflection points, where does the curve change, does it open up or down ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it starts opening down them switches and opens up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0excellent, so you have found the inflection points, can you compute the integral? Where does it start opening up + end + same with down? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay so how do i find the exact point it changes. its \[\infty\] starting then it turns and goes up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0make a table putting the following: x ( put the points you have found, Inflection points) then check what happens to f(x) when you substitute them in the function ^_^ is it ()? (decreasing)? or (+)? (increasing)? ^_^ so if it's positive then it's opening upwards, and the vise versa ^_^ _____________________________________________ f(x) _____________________________________________ f''(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then from the x points you can see from where and where does it open upwards or downwards ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can you give me an example like (0,16)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0those are the x points?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the y of that is 16 according to my calculator

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wait, are you having trouble drawing the function?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, I'm sorry, I'm confused too ^^"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what's does your question really say?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for the answer in the back of the book it says: domain:all real numbers y int.: 16 x int. \[2\sqrt{3}, 2, 2+2\sqrt{3}\] increasing on: (\[\infty,0) and (4,\infty)\] decreasing on (0,4) local maximum at x+0, local minimum at x+4 concaved downward on (\[\infty\], 2) concaved upward on (2, \[\infty\]) inflection pointat x+2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im just trying to figure out how to get those things

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Alright, I got the question, they want you to find the critical points, increasing and decreasing intervals, inflection points, intervals of concavity, domain and range lol :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now i have no clue how to get that

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now for the domain and range, since you'r function is a polunomial then the domain + range = : \[(\infty , \infty)\] 2) To find the critical numbers you've got to derive the function once then take 2 conditions for f'(x) to find the critical numbers a) f'(x) = 0 b) f'(x) = undefined For your question, for all x, x is defined :) , so you'll take condition (a), in this case, f'(x) = 0, then you can find the zeros of your function. Those zeros are your critical numbers. 3) To find the critical points, you have to draw a table, like the one I have showed you before, but instead of f''(x) it's going to be f'(x) and put the critical numbers in the table and the substitute them in the original function to check if you're going to get a () value = decreasing, or a (+) value = increasing. 5) For the inflection numbers, you have to derive once more and take the zeros of the function, same condition for f'(x) ^_^ so those zeros will be your inflection numbers 6) Put these numbers in the table, (the same one I have showed you above) or just put numbers  (any number) 0 and ( + any positive number) then substitute them in the original function to see whether you're getting a + value or negative. + = concaved up,  = concaved down 7) finally just put all the calculations you have found and translate it into a graph These are the steps ^_^ good luck
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