A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

Maximal domain of g(x)... g(x) = (3) - (4/(x+2)) Is it x + 2 = 0.. x = - 2... Is that how we get the maximal domain??

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The maximal domain is the set of all x that allows your function to exist.

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So here, your function is not defined at the point x=-2 since there, the denominator is 0.

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so it can't equal to zero because it's over something

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh okay thanks

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So your domain is the set of all x real except for x=0.

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think real, as long as X not equal to 0

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x+2 not equal to zero

  8. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so is the answer...? R / -2 ?

  9. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  10. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\mathbb{R} - \left\{ -2 \right\}\]

  11. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks :)

  12. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    np

  13. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Also what is it's range? + it wants the inverse...

  14. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is the range infinity to 3 ?

  15. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    negative infinity?

  16. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    u want this (-infinity,2),( 2, infinity)? but i never see a form like that, u just write R-{-2}

  17. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay, do you know how to get the inverse?

  18. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You can use the definition for the inverse. g is the inverse of f if \[f(g(x))=x=g(f(x))\]

  19. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    The inverse of your function can be found then as,\[f(g(x))=3-\frac{4}{g(x)+2}=x\]and solve for g(x).

  20. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    do we put the w hole g(x) under that 4 ?

  21. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

  22. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh sorry.. do we re arrange the g(x) to the other side or something?

  23. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, you solve for g(x)

  24. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    4 = x (g(x)+2)

  25. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where'd you 3 go?

  26. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh lol, -1 = x (g(x) + 2)

  27. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[3-\frac{4}{g(x)+2}=x \rightarrow g(x)=\frac{4}{3-x}-2\]

  28. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    check, i'm being distracted by different people

  29. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    g(x) = 3- 4/x+2.... and inverse is 3 - 4/g(x) +2... can you just leave it like that?

  30. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = 3- (4/x+2) x = 3-(4/y+2) and then simplify

  31. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Take your original function. Put g(x) in place of x and replace f(x) with x Solve (rearrange) so you have g(x) = blah blah

  32. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    how to simplify after... -1 = x(g(x) + 2) ?

  33. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    expand

  34. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x(g(x)+2) = xg(x) + 2x

  35. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    subtract 2x from both sides

  36. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    divide by x

  37. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    but i think you've made a mistake

  38. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I'll write it out

  39. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it wants the inverse g^-1... of g(x) = (3) - (4/(x+2))

  40. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = 3- (4/x+2) x = 3-(4/y+2) x(y+2) = 3-4 x(y+2)=-1 y+2 = -1/x y = (-1/x) -2 can this make sense?

  41. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yeah, same thing, different notation.

  42. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah it makes sense except the G^-1.... the inverse... it looks different.

  43. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y = g^-1(x)

  44. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I stuffed the g(x) calc. because I'm writing it out on this damn thing, but the procedure is correct

  45. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    =) Okay so should I just replace the y's with g(x).. as the answer?

  46. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You should end up with\[g^{-1}(x)=2\frac{x-1}{3-x}\]

  47. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    no no ... don't just replace the y's with g(x)... Do what I said... Take your original function. Put g^-1(x) in place of x and replace f(x) with x Solve (rearrange) so you have g(x) = blah blah

  48. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    it looks difficult to do but okay :)

  49. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    You know what, there's a lot of confusion here. I'm going to write it out and scan.

  50. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thanks :D :D :D I'll wait

  51. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Lokisan are you still there?

  52. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes

  53. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    scanning

  54. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ok alright

  55. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

  56. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Ive reformatted my pc so ill down pdf reader now, thanks for the link.

  57. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ok

  58. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Lokisan, did you use the retro version of this site?

  59. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ?

  60. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    retro

  61. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Yes, there was another version to this site

  62. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That means you joined it after the changes have taken place

  63. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Well, I think the retro was better, as you could type there realtime

  64. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I mean, it was more like a black board, and we didn't have to wait for the whole typing to be over

  65. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh

  66. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Further more we could erase typed things and we could also type inbetween others' typings

  67. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yeah, this is a pain, and i can't use this site on my phone - not practical

  68. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    oh that's heaps better

  69. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Would you mind visiting this one https://docs.google.com/document/d/1-_5IUkf1O4EFkBw-kDEZV1T8THk4lzrpmQEzVKtfHHo/edit?hl=en_GB#

  70. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    I get this: Google Docs has encountered a server error. If reloading the page doesn't help, please contact us. To discuss this or other issues, visit the Google Docs Help forum. To see the list of known problems, go to the Google Docs Known Issues page

  71. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Just try it once again or try refreshing it

  72. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That makes sense now! :D Thanks a lot and nice hand writing :)

  73. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    No probs

  74. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Fan me!

  75. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Okay, I'm a fan already :)

  76. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Good :)

  77. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.