## anonymous 5 years ago ln3x-3lnx+ln3y

1. anonymous

I'm not too sure about what you exactly need. Are you meant to just simplify?

2. anonymous

$\ln 3x -3 \ln x + \ln 3y =\ln 3 + \ln x - 2\ln x + \ln 3 + \ln y$

3. nowhereman

$= \log \frac{9y}{x^2}$

4. anonymous

$=2\ln 3 -2\ln x +\ln y$

5. anonymous

Mistake in the first expression I typed: -2lnx should be -3ln x as in the question.

6. anonymous

$=\ln 3^2-\ln x^2+\ln y= \ln \frac{3^2}{x^2}+\ln y = \ln \frac{3^2y}{x^2}=\ln \frac{9y}{x^2}$