## anonymous 5 years ago find the value of c mean values theorm? (x-1)(x-2)(x-3) [0,4]

1. nowhereman

You have to calculate the elevation of the secant between (0, f(0)) and (4, f(4)). Then differentiate your function and see where the derivative assumes this value.

2. anonymous

i am find the derivate but my value of c is wrong ... f(b)-f(a) / b-a this is the formula now find the c

3. nowhereman

yes, choose a=0 and b=4 and calculate it.

4. anonymous

x3 cube - 6x2 square +11x -6=0 now find value of c x3-6x2+11x-6=0

5. nowhereman

6. anonymous

my prb is what is the value of c just..

7. nowhereman

What do you mean by c? You never said what it is!

8. anonymous

its a formula ok f(c)=f(b)_ f(a) /b-a not find the derivate and put the values

9. nowhereman

You mean $f'(c) = \frac{f(b) - f(a)}{b-a}$ and what is the problem with it? Just insert all the known variables, do the differentiation and solve the resulting quadratic equation!

10. anonymous

iam put the all values f(b)-f(a)/ b-a. what is the answer using quarditic equation

11. nowhereman

So what quadratic equation have you got?

12. anonymous

i have to values of c ..2-2$\sqrt{15}$

13. anonymous

2-2 ander root 15 2+2 under root 15

14. nowhereman

You should check your calculation, the correct solution is $c = 2 \pm \frac 2 3 \sqrt{3}$