need help with factoring following question.
2a^3b^3 + 10ab =

- anonymous

need help with factoring following question.
2a^3b^3 + 10ab =

- Stacey Warren - Expert brainly.com

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- katieb

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- anonymous

you can take 2ab as a common factor so you'll have:
\[2ab(a^2b^2 + 5) = 0\]
^_^

- anonymous

Can you please explain. I am a sub in AEP and cannot help in this subject. This young man does not understand algebra either. He has 6 questions, would you be willing to walk him through these?

- amistre64

What does it mean to "factor" an equation?

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- anonymous

alright, when it comes to factoring, it's more like to write down the expression in its most simplified form.
In other words, we take out what's common from both sides.
What common variables/numbers do we have here? :)

- anonymous

we have in the first part:
\[2a^3b^3\]
and in the second part :
10 ab and 10 can be written as ( 2 x 5)ab
so what do we have in common in both parts? what can we pull out? ^_^

- anonymous

from both parts*

- anonymous

what do we have in common flash? :)

- amistre64

it means to "un"multiply really.
the factors of 16 are all the numbers that multiply together to get 16.
1*16
2*8
4*4
the factors of 16 are: 1,2,4,8, and 16.

- anonymous

lol, I wanted to explain it in a much easier way amistre :)

- amistre64

sstar, youre doing great :)

- anonymous

thank you ^_^, flash did you get it now?

- anonymous

he says he still does not understand.

- amistre64

it would help to know what it is that he doesnt understand, ther are alot of underpinning concepts involved.

- anonymous

i dont understand how to work it

- anonymous

okay , look at this:
2(a)(a)(a)(b)(b)(b) + (2)(5)(a)(b)
to factor, we need to pull out what we have in common, in this case we have 2, a and b common in both sides so we pull out :
2ab
then we're left with :
(a)(a)(b)(b) + (5)
so we can write this down as :
2ab( a^2b^2 + 5 ) ^_^
clear?

- amistre64

i gotta head to class, have fun sstar :)

- anonymous

lol , I will GL amister ^_^

- anonymous

o ok i get it

- anonymous

yay ^_^, so if you want to check your work, you can use the distributive property and it'll get you back to the original form :)

- anonymous

so would a^2b^2+5 be the anwser

- anonymous

no you forgot the 2ab :)
so the answer now is :
\[2ab(a^2b^2 + 5)\]
remember, we pulled out 2ab :) so it'll stay out , clear? ^_^

- anonymous

i feel good...

- anonymous

=D

- anonymous

o ok thank u

- anonymous

lol, a song just hit me when you said that.

- anonymous

it's a pleasure flash ^_^ good luck!

- anonymous

are you saying that you are feeling good andy? or are you singing? ^_^

- anonymous

-30x^2y^2-12xy^2

- anonymous

both

- anonymous

*dancing* *singing* *happy*

- anonymous

my papper is due n 7 min can u giveme the anwsers

- radar

One factor is 6

- radar

What additional factors can you extract from the two terms
\[6___(-5x ^{2}y ^{2}-2xy ^{2})\]

- anonymous

lol andy, you deserve to be so, we all do :)

- radar

6xy^2(-5x-2)

- anonymous

thank u 5cx^2+10c^2x-15c^3

- anonymous

angoo, now to come to think of it, you're doing 3 things and not 2 LOL =D

- radar

5c(x^2+2cx-3c^2)

- radar

If you wait this long to do your work, you need to change that handle Flash!lol

- anonymous

awsome 36a^2b^3c^2-48ab^4c^3+60a^3b^2c

- radar

12ab^2c(3abc-4b^2c^2+5a^2)

- anonymous

thank u 35m^6n^3-49m^3n^4+7m^3n^4

- radar

7m^3n^3(5m^3-7n+n)

- radar

Sorry but I got to go to insurance office.

- anonymous

awsome 33x^2y^4z+55xy^2z^5=66x^6yz^3

- radar

Good luck....will take one more if you have any more. I hope you are reviewing the answers.

- anonymous

33x^2y^4z+55xy^2z^5=66x^6yz^3

- radar

11xyz(3xy^3+5yz^4-6x^5z^2)
Good luck and catch you later.

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