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anonymous
 5 years ago
need help with factoring following question.
2a^3b^3 + 10ab =
anonymous
 5 years ago
need help with factoring following question. 2a^3b^3 + 10ab =

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can take 2ab as a common factor so you'll have: \[2ab(a^2b^2 + 5) = 0\] ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can you please explain. I am a sub in AEP and cannot help in this subject. This young man does not understand algebra either. He has 6 questions, would you be willing to walk him through these?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0What does it mean to "factor" an equation?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0alright, when it comes to factoring, it's more like to write down the expression in its most simplified form. In other words, we take out what's common from both sides. What common variables/numbers do we have here? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0we have in the first part: \[2a^3b^3\] and in the second part : 10 ab and 10 can be written as ( 2 x 5)ab so what do we have in common in both parts? what can we pull out? ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do we have in common flash? :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it means to "un"multiply really. the factors of 16 are all the numbers that multiply together to get 16. 1*16 2*8 4*4 the factors of 16 are: 1,2,4,8, and 16.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, I wanted to explain it in a much easier way amistre :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0sstar, youre doing great :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank you ^_^, flash did you get it now?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0he says he still does not understand.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0it would help to know what it is that he doesnt understand, ther are alot of underpinning concepts involved.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont understand how to work it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay , look at this: 2(a)(a)(a)(b)(b)(b) + (2)(5)(a)(b) to factor, we need to pull out what we have in common, in this case we have 2, a and b common in both sides so we pull out : 2ab then we're left with : (a)(a)(b)(b) + (5) so we can write this down as : 2ab( a^2b^2 + 5 ) ^_^ clear?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i gotta head to class, have fun sstar :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol , I will GL amister ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yay ^_^, so if you want to check your work, you can use the distributive property and it'll get you back to the original form :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so would a^2b^2+5 be the anwser

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no you forgot the 2ab :) so the answer now is : \[2ab(a^2b^2 + 5)\] remember, we pulled out 2ab :) so it'll stay out , clear? ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol, a song just hit me when you said that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's a pleasure flash ^_^ good luck!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0are you saying that you are feeling good andy? or are you singing? ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0*dancing* *singing* *happy*

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0my papper is due n 7 min can u giveme the anwsers

radar
 5 years ago
Best ResponseYou've already chosen the best response.0What additional factors can you extract from the two terms \[6___(5x ^{2}y ^{2}2xy ^{2})\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol andy, you deserve to be so, we all do :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank u 5cx^2+10c^2x15c^3

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0angoo, now to come to think of it, you're doing 3 things and not 2 LOL =D

radar
 5 years ago
Best ResponseYou've already chosen the best response.0If you wait this long to do your work, you need to change that handle Flash!lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0awsome 36a^2b^3c^248ab^4c^3+60a^3b^2c

radar
 5 years ago
Best ResponseYou've already chosen the best response.012ab^2c(3abc4b^2c^2+5a^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thank u 35m^6n^349m^3n^4+7m^3n^4

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Sorry but I got to go to insurance office.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0awsome 33x^2y^4z+55xy^2z^5=66x^6yz^3

radar
 5 years ago
Best ResponseYou've already chosen the best response.0Good luck....will take one more if you have any more. I hope you are reviewing the answers.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.033x^2y^4z+55xy^2z^5=66x^6yz^3

radar
 5 years ago
Best ResponseYou've already chosen the best response.011xyz(3xy^3+5yz^46x^5z^2) Good luck and catch you later.
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