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anonymous

  • 5 years ago

need help with factoring following question. 2a^3b^3 + 10ab =

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  1. anonymous
    • 5 years ago
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    you can take 2ab as a common factor so you'll have: \[2ab(a^2b^2 + 5) = 0\] ^_^

  2. anonymous
    • 5 years ago
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    Can you please explain. I am a sub in AEP and cannot help in this subject. This young man does not understand algebra either. He has 6 questions, would you be willing to walk him through these?

  3. amistre64
    • 5 years ago
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    What does it mean to "factor" an equation?

  4. anonymous
    • 5 years ago
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    alright, when it comes to factoring, it's more like to write down the expression in its most simplified form. In other words, we take out what's common from both sides. What common variables/numbers do we have here? :)

  5. anonymous
    • 5 years ago
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    we have in the first part: \[2a^3b^3\] and in the second part : 10 ab and 10 can be written as ( 2 x 5)ab so what do we have in common in both parts? what can we pull out? ^_^

  6. anonymous
    • 5 years ago
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    from both parts*

  7. anonymous
    • 5 years ago
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    what do we have in common flash? :)

  8. amistre64
    • 5 years ago
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    it means to "un"multiply really. the factors of 16 are all the numbers that multiply together to get 16. 1*16 2*8 4*4 the factors of 16 are: 1,2,4,8, and 16.

  9. anonymous
    • 5 years ago
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    lol, I wanted to explain it in a much easier way amistre :)

  10. amistre64
    • 5 years ago
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    sstar, youre doing great :)

  11. anonymous
    • 5 years ago
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    thank you ^_^, flash did you get it now?

  12. anonymous
    • 5 years ago
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    he says he still does not understand.

  13. amistre64
    • 5 years ago
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    it would help to know what it is that he doesnt understand, ther are alot of underpinning concepts involved.

  14. anonymous
    • 5 years ago
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    i dont understand how to work it

  15. anonymous
    • 5 years ago
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    okay , look at this: 2(a)(a)(a)(b)(b)(b) + (2)(5)(a)(b) to factor, we need to pull out what we have in common, in this case we have 2, a and b common in both sides so we pull out : 2ab then we're left with : (a)(a)(b)(b) + (5) so we can write this down as : 2ab( a^2b^2 + 5 ) ^_^ clear?

  16. amistre64
    • 5 years ago
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    i gotta head to class, have fun sstar :)

  17. anonymous
    • 5 years ago
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    lol , I will GL amister ^_^

  18. anonymous
    • 5 years ago
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    o ok i get it

  19. anonymous
    • 5 years ago
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    yay ^_^, so if you want to check your work, you can use the distributive property and it'll get you back to the original form :)

  20. anonymous
    • 5 years ago
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    so would a^2b^2+5 be the anwser

  21. anonymous
    • 5 years ago
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    no you forgot the 2ab :) so the answer now is : \[2ab(a^2b^2 + 5)\] remember, we pulled out 2ab :) so it'll stay out , clear? ^_^

  22. anonymous
    • 5 years ago
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    i feel good...

  23. anonymous
    • 5 years ago
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    =D

  24. anonymous
    • 5 years ago
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    o ok thank u

  25. anonymous
    • 5 years ago
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    lol, a song just hit me when you said that.

  26. anonymous
    • 5 years ago
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    it's a pleasure flash ^_^ good luck!

  27. anonymous
    • 5 years ago
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    are you saying that you are feeling good andy? or are you singing? ^_^

  28. anonymous
    • 5 years ago
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    -30x^2y^2-12xy^2

  29. anonymous
    • 5 years ago
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    both

  30. anonymous
    • 5 years ago
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    *dancing* *singing* *happy*

  31. anonymous
    • 5 years ago
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    my papper is due n 7 min can u giveme the anwsers

  32. radar
    • 5 years ago
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    One factor is 6

  33. radar
    • 5 years ago
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    What additional factors can you extract from the two terms \[6___(-5x ^{2}y ^{2}-2xy ^{2})\]

  34. anonymous
    • 5 years ago
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    lol andy, you deserve to be so, we all do :)

  35. radar
    • 5 years ago
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    6xy^2(-5x-2)

  36. anonymous
    • 5 years ago
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    thank u 5cx^2+10c^2x-15c^3

  37. anonymous
    • 5 years ago
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    angoo, now to come to think of it, you're doing 3 things and not 2 LOL =D

  38. radar
    • 5 years ago
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    5c(x^2+2cx-3c^2)

  39. radar
    • 5 years ago
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    If you wait this long to do your work, you need to change that handle Flash!lol

  40. anonymous
    • 5 years ago
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    awsome 36a^2b^3c^2-48ab^4c^3+60a^3b^2c

  41. radar
    • 5 years ago
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    12ab^2c(3abc-4b^2c^2+5a^2)

  42. anonymous
    • 5 years ago
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    thank u 35m^6n^3-49m^3n^4+7m^3n^4

  43. radar
    • 5 years ago
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    7m^3n^3(5m^3-7n+n)

  44. radar
    • 5 years ago
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    Sorry but I got to go to insurance office.

  45. anonymous
    • 5 years ago
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    awsome 33x^2y^4z+55xy^2z^5=66x^6yz^3

  46. radar
    • 5 years ago
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    Good luck....will take one more if you have any more. I hope you are reviewing the answers.

  47. anonymous
    • 5 years ago
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    33x^2y^4z+55xy^2z^5=66x^6yz^3

  48. radar
    • 5 years ago
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    11xyz(3xy^3+5yz^4-6x^5z^2) Good luck and catch you later.

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