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jeremy
 5 years ago
find the roots of
f(x)=x^46x^310x^2+2x15
jeremy
 5 years ago
find the roots of f(x)=x^46x^310x^2+2x15

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have the same problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are 4 roots in this

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x ~~ 1.9134607252052312 x ~~ 7.3594940468468407 x ~~ 0.276983339179195240.99421429099634553 i x ~~ 0.27698333917919524+0.99421429099634553 i are the four roots, and th elast two are imaginary, ( the reason i've typed an 'i' there)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0there are ways you can improve your odds when searching for roots; I forget the names they give to them, but, it has something to do with the number of times the signs switch; and factors and fractions of first/last....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.01,3,5,15 1,3,5,15 then use synthetic division to weed them out if possible :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes u r right, amistre

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the highest power x has , is the no. of roots u get

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the number of "possible" roots, yes.... but we can have no roots as well :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no roots at all ? not even imaginary ??

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0"we dont need no stinkin' toots"  anonymous take x^2 +5 for example, .... ro :real" roots :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0i feel like i have an iphone doing atuo correct on me lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Refer to the attachment, jeremy.pdf The two real roots are clearly visible. Thinker has them nailed. The root 7.35.. yields a function value very close to zero. \[f(7.35949) = 1.13687 * 10^{13}\] By eye ball, one can see where the three derivatives are zero and the two inflection points. P.S. If everyone had access to a copy of Mathematica V8, I would venture to guess that there would be very few problems posted to this site. I have no financial connections to Wolfram.
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