use the implicit differentiation to find the equation of the tangent line to the curve xy^3+xy=10at point (5,1)

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

use the implicit differentiation to find the equation of the tangent line to the curve xy^3+xy=10at point (5,1)

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

what do you know about implicit differentation?
differentiate it and subs the point (5,1) . am i right? @amistre
yep, thats right think

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

differentiate like normal, just keep your x' and y' in the problem...
y-1=-(x-5)/10
D(xy^3) + D(xy) = D(10) product rule ... product rule....constant rule
simplify and differentiate, 10y-10=-x-5 => x+10y=5now try to differentiate...will that do @amistre?
you CAN try to seperate it all, but its really just easier to work the problam as it...
(x'y + xy') + (x'y + xy') = D(10) = 0
x'(y^3) + x(3y^2)y' + x'y + xy' = 0
yeah this is fine even..whatever u find easy diddy :)
x' = dx/dx = 1 like any good fraction... now solve for y'
hey catch u later ..gotta go :) bye all
Ciao think :)
thanks @ thinker
ur welcome ..@diddy, all the best and ciao amistre...ttyl maybe after 2 days :)
Its important to realize that there is nothing that special when doing implicits.. for example: D(x^4) = x' 4x^3 D(3y^2) = y' 6y D(3xy) = 3xy' + x'3y D(y) = y' D(x) = x' its all normal rules
oki so i used this form amistre x'(y^3) + x(3y^2)y' + x'y + xy' = 0 and i came up with 2y^3/3xy^2+1, but i'm not sure that's right
Let me double check the work... x'(y^3) + x(3y^2)y' + x'y + xy' = 0 y^3 + y'(3xy^2) + y + y'x = 0 y'(3xy^2) + y'x = -y^3 - y y'(3xy^2 + x) = -y^3 -y -y^3 -y y' = ----------- 3xy^2 + x did I make any mistakes in this?
You didn't :)
yay!!... lately, thats an accomplishment :)
yea i think that's right, make sense now thanks :)
now plug in your x and y values to determine the slope of the tangent line at that point :)
ook got it
good job :)
YAY i got it!!! thanks u're the best :)
now, now... youre only saying that cause its true lol :)
lol
i'm having some trouble with this one... Find the slope of the tangent line to the curve -1x^2-2xy-3y^3=-185 at the point (-1,4).
never mind, got it!!!

Not the answer you are looking for?

Search for more explanations.

Ask your own question