anonymous
  • anonymous
Solve 56x + x^3 = 15x^2 by factoring
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Wouldn't it be x(56+x^2) = (I don't know the rest)
anonymous
  • anonymous
i think i got it: x(56+x^2)=15x divide by x both sides so: x(56+x^2)/x=15x/x then you get 56+x^2=15x arrange:i.e x^2-15x+56=0 1*56=56 -8+-7=-15 insert:x^2-8x-7x+56=0 x is common.... x(x-8)......-7(x-8)=0 (x-7)...(x-8)=0 since (x-7)=0 x=7 since (x-8)=0 x=8 possible values of x are: 8 & 7
anonymous
  • anonymous
sorry the division part is suppposed to be: x(56+x^2)=15x^2 then divide by x both sides you get: 56+x^2=15x the rest is ok

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