anonymous
  • anonymous
4e^(x-1)=64
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
x=(ln16)+1
anonymous
  • anonymous
How did you get that?
anonymous
  • anonymous
e^(x-1)=16 then you ln both side -> x-1=ln16 x=(ln16) +1

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anonymous
  • anonymous
ummmmmmm yeah still not getting it.
anonymous
  • anonymous
What you mean?
anonymous
  • anonymous
like for instance where did the ln come from and why is it hooking up with the 16. Then why are you replacing x with ln16?
anonymous
  • anonymous
e^(x-1) =64/4 Then you take the natural log(or ln) of both side, because ln(e^x)=x which is an identity, so you got x-1= ln 16 then you solve for x by adding 1 to both side
anonymous
  • anonymous
http://en.wikipedia.org/wiki/Natural_logarithm you can check this out if you dont know the identity
anonymous
  • anonymous
okay thank you for your help its highly appreciated!! :0]
anonymous
  • anonymous
:)
anonymous
  • anonymous
divide both sides by 4 you are left with....e^x-1=16......then introduce the natural log on both sides

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