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anonymous

  • 5 years ago

4e^(x-1)=64

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  1. anonymous
    • 5 years ago
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    x=(ln16)+1

  2. anonymous
    • 5 years ago
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    How did you get that?

  3. anonymous
    • 5 years ago
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    e^(x-1)=16 then you ln both side -> x-1=ln16 x=(ln16) +1

  4. anonymous
    • 5 years ago
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    ummmmmmm yeah still not getting it.

  5. anonymous
    • 5 years ago
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    What you mean?

  6. anonymous
    • 5 years ago
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    like for instance where did the ln come from and why is it hooking up with the 16. Then why are you replacing x with ln16?

  7. anonymous
    • 5 years ago
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    e^(x-1) =64/4 Then you take the natural log(or ln) of both side, because ln(e^x)=x which is an identity, so you got x-1= ln 16 then you solve for x by adding 1 to both side

  8. anonymous
    • 5 years ago
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    http://en.wikipedia.org/wiki/Natural_logarithm you can check this out if you dont know the identity

  9. anonymous
    • 5 years ago
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    okay thank you for your help its highly appreciated!! :0]

  10. anonymous
    • 5 years ago
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    :)

  11. anonymous
    • 5 years ago
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    divide both sides by 4 you are left with....e^x-1=16......then introduce the natural log on both sides

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