anonymous
  • anonymous
Find the function with the following Maclaurin series starting with the Maclaurin series for sinx: 1-[((5^3)(x^3))/3!]-[((5^5)(x^5))/5!]+[((5^7)(x^7))/7!]-...
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
good question. sorry I can't answer it for you
anonymous
  • anonymous
Are you sure of the signs of each term?
anonymous
  • anonymous
Yes. I've figured it out. the answer was 1-sin(3x).

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anonymous
  • anonymous
1-[((5^3)(x^3))/3!]-[((5^5)(x^5))/5!]+[((5^7)(x^7))/7!]-... The signs are not correct...and sorry, it cannot be 1-sin(3x). The series expansion for sin x is sinx = x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ... If i assume the signs are alternating, the answer might be 1 - 3x + sin(3x) or 1 + 3x - sin(3x)
anonymous
  • anonymous
yes the question was suppose to be alternating. the answer I posted above was indeed correct according the the answer booklet.

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