Find the function with the following Maclaurin series starting with the Maclaurin series for sinx: 1-[((5^3)(x^3))/3!]-[((5^5)(x^5))/5!]+[((5^7)(x^7))/7!]-...

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

Find the function with the following Maclaurin series starting with the Maclaurin series for sinx: 1-[((5^3)(x^3))/3!]-[((5^5)(x^5))/5!]+[((5^7)(x^7))/7!]-...

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

good question. sorry I can't answer it for you
Are you sure of the signs of each term?
Yes. I've figured it out. the answer was 1-sin(3x).

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

1-[((5^3)(x^3))/3!]-[((5^5)(x^5))/5!]+[((5^7)(x^7))/7!]-... The signs are not correct...and sorry, it cannot be 1-sin(3x). The series expansion for sin x is sinx = x - (x^3)/3! + (x^5)/5! - (x^7)/7! + ... If i assume the signs are alternating, the answer might be 1 - 3x + sin(3x) or 1 + 3x - sin(3x)
yes the question was suppose to be alternating. the answer I posted above was indeed correct according the the answer booklet.

Not the answer you are looking for?

Search for more explanations.

Ask your own question