anonymous
  • anonymous
Find the slope of the tangent line to the curve 2x^4-3x^2+sq.x-5/x^2 at point (1,-5)
Mathematics
schrodinger
  • schrodinger
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amistre64
  • amistre64
is the x^2 the denominator of everything else?
anonymous
  • anonymous
no just the denominator of 5
amistre64
  • amistre64
ok...so the last term is 5/x^2 everything else is as is..

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anonymous
  • anonymous
i was thinking about rewriting it as 5x^-2, but i'm not sure
anonymous
  • anonymous
correct
amistre64
  • amistre64
go ahead, its all good :)
anonymous
  • anonymous
ook cool
amistre64
  • amistre64
8x^3 -6x +(1/2sqrt(x)) +(10/x^3) is what i get... maybe its right?
anonymous
  • anonymous
yea i got 8x^3-6x+1/2x^-1/2-10x^-3, should i substitute after this?
amistre64
  • amistre64
yep, but I think you only need the "x" value
amistre64
  • amistre64
8 -6 + (1/2) +10
anonymous
  • anonymous
yea so just substitute the x value
amistre64
  • amistre64
and youve got a typo,,,that last term should be a (+); -5(-2)=10
anonymous
  • anonymous
oh yea thanks
amistre64
  • amistre64
I get 6 as the slope... if I did it right :)
anonymous
  • anonymous
uhm i'm not sure if we're doing it right cuz the problem is actually asking me for the equation of the line
amistre64
  • amistre64
the derivative is the equation of the slope of the line; or maybe it should be in y = mx+b format?
anonymous
  • anonymous
yea i think that's what they mean y=mx+b format
amistre64
  • amistre64
y = 6x +b at (x=1,y=-5)?? -5 = 6(1) + b -5 = 6 + (-11) y = 6x-11 then
anonymous
  • anonymous
hold up, how did u get 6 as the slope, i'm up to 8-6+1/2+10
amistre64
  • amistre64
f'(x) = m 8-6=2+10=12...ahhh, I see; I multiplied by 1/2
amistre64
  • amistre64
12.5 happy :)
anonymous
  • anonymous
ook cool
anonymous
  • anonymous
lol
amistre64
  • amistre64
-5 = 12.5(1) + b -5 -12.5 = b -17.5 = b y = 12.5 - 17.5...
amistre64
  • amistre64
squeeze an "x" right up next to that 12.5
amistre64
  • amistre64
or do they want it in Ax + By = C format?
anonymous
  • anonymous
y=mx+b format
amistre64
  • amistre64
you can use the line equation to figure out a new "x value" when iterating a function solve it...
anonymous
  • anonymous
uhm not sure about that... does that mean that y=6x-11 is not it
amistre64
  • amistre64
yeah, since i miscalculated the first time with a "6", its a bad apple...toss it out before it spoils the rest :)
anonymous
  • anonymous
ook
anonymous
  • anonymous
ok then it's 8-6+1/2+10=12+1/2=25/2
anonymous
  • anonymous
so the slope is 25/2
anonymous
  • anonymous
got it thanks :)

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