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anonymous

  • 5 years ago

find the area of r that is bounded by the graph of y=x^2-1 and the graph of x=y^2

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  1. anonymous
    • 5 years ago
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    is this for single or multi-variable calculus?

  2. amistre64
    • 5 years ago
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    do I dare? :)

  3. nowhereman
    • 5 years ago
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    It's single variable calculus.

  4. amistre64
    • 5 years ago
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    this would be easier if we do it with respect to the y axis right?

  5. anonymous
    • 5 years ago
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    I don't think so.

  6. amistre64
    • 5 years ago
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    I get pretty little intervals on the up and down tho ....

  7. anonymous
    • 5 years ago
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    Err. Oh. Yes, doing it with respect to y is best. I misread the equation.

  8. anonymous
    • 5 years ago
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    if this is for multi-variable, I would integrate w.r.t. x first, if it is for single- then use the little formula for area between two curves wr.t .y

  9. anonymous
    • 5 years ago
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    It's single variable.

  10. anonymous
    • 5 years ago
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    @ polpak, Is this your question?

  11. amistre64
    • 5 years ago
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    is this equivalent to: y=x^2 y = sqrt(x-1) ?? I think I did it right, but aint sure...

  12. amistre64
    • 5 years ago
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    y=sqrt(x+1) wrote down wrong.... im good

  13. anonymous
    • 5 years ago
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    \[f_1(y) = \sqrt{1+y}\] \[f_2(y) = y^2\]

  14. anonymous
    • 5 years ago
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    agreed

  15. amistre64
    • 5 years ago
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    I see the points on the paper, I just cant get to them :)

  16. amistre64
    • 5 years ago
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    x^4 -2x^3 -x +1 = 0 .... is this even right yet?

  17. amistre64
    • 5 years ago
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    can we modify this with trig? use polar coordinates? just wondering.. If we add the functions together, can we get the area that way?

  18. amistre64
    • 5 years ago
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    not adding i guess... maybe subtracting :)

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