## anonymous 5 years ago find the area of r that is bounded by the graph of y=x^2-1 and the graph of x=y^2

1. anonymous

is this for single or multi-variable calculus?

2. amistre64

do I dare? :)

3. nowhereman

It's single variable calculus.

4. amistre64

this would be easier if we do it with respect to the y axis right?

5. anonymous

I don't think so.

6. amistre64

I get pretty little intervals on the up and down tho ....

7. anonymous

Err. Oh. Yes, doing it with respect to y is best. I misread the equation.

8. anonymous

if this is for multi-variable, I would integrate w.r.t. x first, if it is for single- then use the little formula for area between two curves wr.t .y

9. anonymous

It's single variable.

10. anonymous

@ polpak, Is this your question?

11. amistre64

is this equivalent to: y=x^2 y = sqrt(x-1) ?? I think I did it right, but aint sure...

12. amistre64

y=sqrt(x+1) wrote down wrong.... im good

13. anonymous

$f_1(y) = \sqrt{1+y}$ $f_2(y) = y^2$

14. anonymous

agreed

15. amistre64

I see the points on the paper, I just cant get to them :)

16. amistre64

x^4 -2x^3 -x +1 = 0 .... is this even right yet?

17. amistre64

can we modify this with trig? use polar coordinates? just wondering.. If we add the functions together, can we get the area that way?

18. amistre64

not adding i guess... maybe subtracting :)