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anonymous
 5 years ago
find the area of r that is bounded by the graph of y=x^21 and the graph of x=y^2
anonymous
 5 years ago
find the area of r that is bounded by the graph of y=x^21 and the graph of x=y^2

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is this for single or multivariable calculus?

nowhereman
 5 years ago
Best ResponseYou've already chosen the best response.0It's single variable calculus.

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0this would be easier if we do it with respect to the y axis right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I get pretty little intervals on the up and down tho ....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Err. Oh. Yes, doing it with respect to y is best. I misread the equation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if this is for multivariable, I would integrate w.r.t. x first, if it is for single then use the little formula for area between two curves wr.t .y

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It's single variable.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0@ polpak, Is this your question?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0is this equivalent to: y=x^2 y = sqrt(x1) ?? I think I did it right, but aint sure...

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y=sqrt(x+1) wrote down wrong.... im good

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[f_1(y) = \sqrt{1+y}\] \[f_2(y) = y^2\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I see the points on the paper, I just cant get to them :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^4 2x^3 x +1 = 0 .... is this even right yet?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0can we modify this with trig? use polar coordinates? just wondering.. If we add the functions together, can we get the area that way?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0not adding i guess... maybe subtracting :)
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