summation series question: for the following equation do i use geometric series theorem, telescoping or harmonic methods? the problem is: (sorry idk how to illustrate summation LOL)
infinity
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`. { (1/2^k)-1/(2^k+1) }
/
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k=1

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Is your summation,\[\sum_{k=1}^{\infty}\left( \frac{1}{2^k}-\frac{1}{2^{k+1}} \right)\]?

So for the first N summations, you would have,\[\sum_{k=1}^{N}:=\frac{1}{2}-\frac{1}{2^{N+1}}\]

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