## anonymous 5 years ago The directions say simplify. I didn't know how to type this so over means like a fraction and the brackets should cover both upper and lower numbers. {-3(a^2b^-1)^3}^-2 over {7(a^-5b^6)^-1}

1. anonymous

Is this it? $\frac{[-3(a^2b^{-1})^3]^{-2}}{7(a^{-5}b^6)^{-1}}$

2. anonymous

No the brackets are over the bottom too so that the whole fraction is to the ^-2

3. anonymous

Ok so $[\frac{-3(a^2b^{-1})^{3}}{7(a^{-5}b^6)^{-1}}]^{-2}$

4. anonymous

Yes that's it

5. anonymous

So start with what's inside the brackets. Specifically work on the numerator. What do you have when you evaluate $(a^2b^{-1})^3 = ?$

6. anonymous

(a^6b^-3)

7. anonymous

Correct. Now the denominator.

8. anonymous

(a^-5b^-6

9. anonymous

Not quite.

10. anonymous

(a^-5b^6)

11. anonymous

Sorry I have to leave I'll have to come back to this later

12. anonymous

$(a^{-5}b^6)^{-1} = a^{\text{-5 * -1}}b^{\text{6*-1}}$